tf.math.tanh
Stay organized with collections Save and categorize content based on your preferences.
Computes hyperbolic tangent of x element-wise.
tf.math.tanh( x: Annotated[Any, tf.raw_ops.Any], name=None ) -> Annotated[Any, tf.raw_ops.Any]
Used in the notebooks
Given an input tensor, this function computes hyperbolic tangent of every element in the tensor. Input range is [-inf, inf] and output range is [-1,1].
x = tf.constant([-float("inf"), -5, -0.5, 1, 1.2, 2, 3, float("inf")]) tf.math.tanh(x) <tf.Tensor: shape=(8,), dtype=float32, numpy= array([-1.0, -0.99990916, -0.46211717, 0.7615942 , 0.8336547 , 0.9640276 , 0.9950547 , 1.0], dtype=float32)>
Args |
|---|
x | A Tensor. Must be one of the following types: bfloat16, half, float32, float64, complex64, complex128. |
name | A name for the operation (optional). |
Returns |
|---|
A Tensor. Has the same type as x. If x is a SparseTensor, returns SparseTensor(x.indices, tf.math.tanh(x.values, ...), x.dense_shape) |
Except as otherwise noted, the content of this page is licensed under the Creative Commons Attribution 4.0 License, and code samples are licensed under the Apache 2.0 License. For details, see the Google Developers Site Policies. Java is a registered trademark of Oracle and/or its affiliates. Some content is licensed under the numpy license.
Last updated 2024-04-26 UTC.
[[["Easy to understand","easyToUnderstand","thumb-up"],["Solved my problem","solvedMyProblem","thumb-up"],["Other","otherUp","thumb-up"]],[["Missing the information I need","missingTheInformationINeed","thumb-down"],["Too complicated / too many steps","tooComplicatedTooManySteps","thumb-down"],["Out of date","outOfDate","thumb-down"],["Samples / code issue","samplesCodeIssue","thumb-down"],["Other","otherDown","thumb-down"]],["Last updated 2024-04-26 UTC."],[],[]]
