Pow(x, n)

Implement pow(x, n), which calculates x raised to the power n (i.e., xn).

Example 1:

Input: x = 2.00000, n = 10
Output: 1024.00000

Example 2:

Input: x = 2.10000, n = 3
Output: 9.26100

Example 3:

Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25

Constraints:

• -100.0 < x < 100.0
• -231 <= n <= 231-1
• -104 <= xn <= 104

SOLUTION:

class Solution: def myPow(self, x: float, n: int) -> float: if n < 0: return 1 / self.myPow(x, -n) if n == 0: return 1 if n % 2 == 0: curr = self.myPow(x, n // 2) return curr * curr else: curr = self.myPow(x, (n - 1) // 2) return x * curr * curr