Given an array of n integers nums, a 132 pattern is a subsequence of three integers nums[i], nums[j] and nums[k] such that i < j < k and nums[i] < nums[k] < nums[j].
Return true if there is a 132 pattern in nums, otherwise, return false.
Example 1:
Input: nums = [1,2,3,4]
Output: false
Explanation: There is no 132 pattern in the sequence.
Example 2:
Input: nums = [3,1,4,2]
Output: true
Explanation: There is a 132 pattern in the sequence: [1, 4, 2].
Example 3:
Input: nums = [-1,3,2,0]
Output: true
Explanation: There are three 132 patterns in the sequence: [-1, 3, 2], [-1, 3, 0] and [-1, 2, 0].
Constraints:
-
n == nums.length -
1 <= n <= 2 * 105 -
-109 <= nums[i] <= 109
SOLUTION:
class Solution: def find132pattern(self, nums: List[int]) -> bool: n = len(nums) if n < 3: return False stack = [] k = -1 for i in range(n - 1, -1, -1): if k > -1 and nums[k] > nums[i]: return True while len(stack) > 0 and nums[i] > nums[stack[-1]]: k = stack.pop() stack.append(i) return False # class Solution: # def makeSeg(self, arr, i, j): # seg = self.seg # if (i, j) in seg: # return seg[(i, j)] # if i == j: # seg[(i, j)] = arr[i] # return arr[i] # mid = (i + j) // 2 # curr = max(self.makeSeg(arr, i, mid), self.makeSeg(arr, mid + 1, j)) # seg[(i, j)] = curr # return curr # def getMax(self, arr, i, j, ni, nj): # seg = self.seg # if ni >= i and nj <= j: # return seg[(ni, nj)] # if (ni < i and nj < i) or (ni > j and nj > j): # return float('-inf') # mid = (ni + nj) // 2 # return max(self.getMax(arr, i, j, ni, mid), self.getMax(arr, i, j, mid + 1, nj)) # def find132pattern(self, nums: List[int]) -> bool: # n = len(nums) # self.seg = {} # self.makeSeg(nums, 0, n - 1) # for i in range(n): # for j in range(i + 2, n): # if nums[j] > nums[i] and self.getMax(nums, i, j, 0, n - 1) > nums[j]: # return True # return False # class Solution: # def find132pattern(self, nums: List[int]) -> bool: # n = len(nums) # next_lowest = [n for i in range(n)] # stack = [] # for i in range(n): # while len(stack) > 0 and nums[i] < nums[stack[-1]]: # curr = stack.pop() # next_lowest[curr] = i # for j in range(curr): # if nums[j] < nums[i]: # return True # stack.append(i) # return False # class Solution: # def find132pattern(self, nums: List[int]) -> bool: # currMin = float('inf') # currMax = float('-inf') # for num in nums: # currMin = min(currMin, num) # currMax = max(currMax, num) # if num > currMin and num < currMax: # return True # return False
Top comments (0)