Given a string s
, find the longest palindromic subsequence's length in s
.
A subsequence is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements.
Example 1:
Input: s = "bbbab"
Output: 4
Explanation: One possible longest palindromic subsequence is "bbbb".
Example 2:
Input: s = "cbbd"
Output: 2
Explanation: One possible longest palindromic subsequence is "bb".
Constraints:
-
1 <= s.length <= 1000
-
s
consists only of lowercase English letters.
SOLUTION:
class Solution: cache = {} def maxPalindrome(self, s, i, j): key = 1100 * i + j if (key) in self.cache: return self.cache[key] if i == j: self.cache[key] = 1 elif s[i] == s[j] and i + 1 == j: self.cache[key] = 2 elif s[i] == s[j]: self.cache[key] = self.maxPalindrome(s, i + 1, j - 1) + 2 else: self.cache[key] = max(self.maxPalindrome(s, i, j - 1), self.maxPalindrome(s, i + 1, j)) return self.cache[key] def longestPalindromeSubseq(self, s: str) -> int: self.cache.clear() return self.maxPalindrome(s, 0, len(s) - 1)
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