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Cook Off

kyra-ptn edited this page Aug 30, 2024 · 2 revisions

U-nderstand

Understand what the interviewer is asking for by using test cases and questions about the problem.

  • Q:
    • What is the desired outcome?
      • To find the maximum number of copies of target_meal that can be created using the given ingredients.
  • Q:
    • What input is provided?
      • Two strings, ingredients and target_meal.

P-lan

Plan the solution with appropriate visualizations and pseudocode.

General Idea: Count the frequency of each character in ingredients and target_meal, then determine how many times target_meal can be formed by dividing the counts.

1) Count the frequency of each character in `ingredients` and `target_meal`. 2) Initialize `max_copies` to infinity. 3) For each character in `target_meal`, check if it is present in `ingredients`. - If not, return 0. - Otherwise, update `max_copies` with the minimum value of the integer division of the counts. 4) Return `max_copies`.

⚠️ Common Mistakes

  • Not correctly handling the case where a character in target_meal is missing from ingredients.

I-mplement

def max_attempts(ingredients, target_meal): # Step 1: Manually count the frequency of each character in ingredients ingredients_count = {} for char in ingredients: if char in ingredients_count: ingredients_count[char] += 1 else: ingredients_count[char] = 1 # Step 2: Manually count the frequency of each character in target_meal target_meal_count = {} for char in target_meal: if char in target_meal_count: target_meal_count[char] += 1 else: target_meal_count[char] = 1 max_copies = float('inf') # Step 3: Calculate the maximum number of times the target meal can be made for char in target_meal_count: if char not in ingredients_count: return 0 max_copies = min(max_copies, ingredients_count[char] // target_meal_count[char]) return max_copies
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