Posted on Aug 8, 2019

Daily Challenge #36 - Let's go for a run!

Today's challenge requires you to calculate one's running pace.

For example:

runningPace(distance, time)
distance - A float with the number of kilometres
time - A string containing the time it took to travel the distance; it will always be minutes:seconds

The function should return the pace, "5:20" means it took 5 minutes and 20 seconds to travel one kilometre.

Happy Coding!

This challenge comes from jtauri on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge for a future post? Email yo+challenge@dev.to with your suggestions!

Top comments (9)

Dane Hillard • Aug 8 '19 • Edited

def running_pace(distance, time): minutes, seconds = [int(part) for part in time.split(':')] total_seconds = minutes * 60 + seconds seconds_per_km = total_seconds / distance pace_minutes = int(seconds_per_km // 60) pace_seconds = int(seconds_per_km % 60) return f'{pace_minutes}:{pace_seconds:02d}'

La blatte • Aug 8 '19 • Edited

Here it goes!

runningPace = (distance, time) => { const [minutes, seconds] = time.split(':').map((p) => parseInt(p)); const total = 60 * minutes + seconds; const pace = total / distance; return `${Math.floor(pace / 60)}:${('00' + Math.floor(pace % 60)).slice(-2)}` }

Mat-R-Such • May 3 '20

Python

def runningPace(distance, time): time= time.split(':') time=int(time[0])*60+int(time[1]) pace=int(time/distance) m=pace//60 s=str(pace-(m*60)) if int(s)<10: s='0'+str return '%d:%s' %(m,s)

Lisa Benmore • Aug 8 '19

Not brilliant but...

function runningPace (distance, time) { const twoDigits = num => String(num).length < 2 ? '0' + num : num; const mins = parseInt(time.split(':')[0]); const secs = parseInt(time.split(':')[1]); const totalSecs = (mins * 60) + secs; const timePerKm = totalSecs / parseInt(distance); const results = [ twoDigits(Math.floor(timePerKm / 60)), twoDigits(Math.round(timePerKm % 60)) ]; return results.join(':'); }

peter279k • Jun 19 '20

Here is the simple solution with JavaScript:

function runningPace(distance, time) { if (distance === 1) { return time; } var timeArray = time.split(':'); var minute = Number(timeArray[0]) * 60 var seconds = Number(timeArray[1]) + minute seconds = Math.floor(seconds / distance); minute = Math.floor(seconds / 60); var second = seconds - minute * 60; if (second >= 0 && second <= 9) { second = "0" + String(second); } return minute + ":" + second; }

Héctor Pascual • Aug 13 '19

Python :

def running_pace(distance, time): time_split = time.split(':') time_parsed = float(time_split[0])+float(time_split[1])/60 time_1km = time_parsed/distance #1 km divided speed in [km / m]  seconds_1_km = int(float(str(time_1km - int(time_1km))[1:])*60) minutes_1_km = int(time_1km) return f"{minutes_1_km}:{seconds_1_km}"

Seiei Miyagi • Aug 8 '19 • Edited

Ruby <3

def runningPace(d, t) t.split ?: |> map &:to_r |> then { @1 * 60 + @2 |> quo d |> divmod 60 |> then &"%02d:%02d".:% } end

Maneesh Kumar 🇮🇳 • Aug 9 '19

function runningPace(distance, time){
const dist = distance * 1000; //in meters
const timeInSecond =parseInt(time.split(':')[0]) * 60 + parseInt(time.split(':')[1]); //in seconds
const pace = dist / timeInSecond;
return pace

Ian Fabs • Aug 8 '19

I know these don't get many likes, but I really appreciate these. Like really appreciate them!