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Daily Challenge #222 - Parse Bank Account Numbers

#challenge

You work for a bank, which has recently purchased an ingenious machine to assist in reading letters and faxes sent in by branch offices.

The machine scans the paper documents, and produces a string with a bank account that looks like this:

 _ _ _ _ _ _ _ | _| _||_||_ |_ ||_||_| ||_ _| | _||_| ||_| _|

... why did we buy this machine?

Anyway, your task is to write a function that can take bank account string and parse it into actual account numbers.

Example

 _ _ _ _ _ _ _ _ _ | | _| _|| ||_ |_ ||_||_| => 23056789 |_||_ _||_| _||_| ||_| _|

Tests

 _ _ _ _ _ _ _ _ _ |_| _| _||_||_ |_ |_||_||_| |_||_ _||_| _||_| _||_| _| _ _ _ _ _ _ _ | _| _||_||_ |_ ||_||_| ||_ _| | _||_| ||_| _|

Good luck!

This challenge comes from arhigod on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge idea for a future post? Email yo+challenge@dev.to with your suggestions!

Top comments (3)

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qm3ster profile image
Mihail Malo • • Edited

Rust. Who needs error checking when you can support multiline instead?

use itertools::{izip, Itertools}; // 0.9.0 fn smol(big: &str) -> String { big.lines() .tuples() .flat_map(|(l1, l2, l3)| { izip!(l1.chars(), l2.chars(), l3.chars()) .tuples() .map(|digit| match digit { ((' ', ' ', ' '), (' ', ' ', ' '), (' ', '|', '|')) => '1', ((' ', ' ', '|'), ('_', '_', '_'), (' ', '|', ' ')) => '2', ((' ', ' ', ' '), ('_', '_', '_'), (' ', '|', '|')) => '3', ((' ', '|', ' '), (' ', '_', ' '), (' ', '|', '|')) => '4', ((' ', '|', ' '), ('_', '_', '_'), (' ', ' ', '|')) => '5', ((' ', '|', '|'), ('_', '_', '_'), (' ', ' ', '|')) => '6', ((' ', ' ', ' '), ('_', ' ', ' '), (' ', '|', '|')) => '7', ((' ', '|', '|'), ('_', '_', '_'), (' ', '|', '|')) => '8', ((' ', '|', ' '), ('_', '_', '_'), (' ', '|', '|')) => '9', x => unreachable!(), }) }) .collect() } fn main() { println!( "{}", smol( r" _ _ _ _ _ _ _ | _| _||_||_ |_ ||_||_| ||_ _| | _||_| ||_| _| _ _ _ _ _ _ _ | _| _||_||_ |_ ||_||_| ||_ _| | _||_| ||_| _| _ _ _ _ _ _ _ | _| _||_||_ |_ ||_||_| ||_ _| | _||_| ||_| _|" ) ); }

Look at it go

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vidit1999 profile image
Vidit Sarkar • • Edited

Python solution

# stores the modified string representation of a digit digitStringDict = { " _ | ||_|" : "0", " | |" : "1", " _ _||_ " : "2", " _ _| _|" : "3", " |_| |" : "4", " _ |_ _|" : "5", " _ |_ |_|" : "6", " _ | |" : "7", " _ |_||_|" : "8", " _ |_| _|" : "9" } # takes a multiline string as input # outputs the int representation of that def stringToAccountNumber(account: str) -> int: account = account.strip("\n") parts = account.split("\n") # split the actual string into three strings based on new-line character  numberStr = "" # stores the string representation of the number  for i in range(0,len(parts[0]),3): numberStr += digitStringDict[parts[0][i:i+3]+parts[1][i:i+3]+parts[2][i:i+3]] return int(numberStr)

Output,

test1 = ''' _ _ _ _ _ _ _ _ _ |_| _| _||_||_ |_ |_||_||_| |_||_ _||_| _||_| _||_| _| ''' test2 = ''' _ _ _ _ _ _ _ | _| _||_||_ |_ ||_||_| ||_ _| | _||_| ||_| _| ''' test3 = ''' _ _ _ _ _ _ _ _ _ | | _| _|| ||_ |_ ||_||_| |_||_ _||_| _||_| ||_| _| ''' print(stringToAccountNumber(test1)) # output -> 823856989 print(stringToAccountNumber(test2)) # output -> 123456789 print(stringToAccountNumber(test3)) # output -> 23056789
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peritract profile image
Dan Keefe • • Edited

This is a rather hacky Python solution that relies on a dictionary of strings mapping to digits. I made the assumption that input would come as an array of strings, one for each level of the digits.

Code 

digit_dict = {" _ | | _ ": 0, " | |": 1, " _ _||_ ": 2, " _ _| _|": 3, " |_| |": 4, " _ |_ _|": 5, " _ |_ |_|": 6, " _ | |": 7, " _ |_||_|": 8, " _ |_| _|" : 9} def parse_bank_code(str_list, digit_dict): """ Function that takes awkward digit string and and digit dict; returns a normal string of digits. """ digits = [] # Holder for digits # Loop through three places at a time for i in range(0, len(str_list[0]), 3): # Take three characters from each level as a list digit = [x[i:i+3] for x in str_list] # Join the characters together and get the dict value digit = digit_dict["".join(digit)] # Add the digit as a string to the list digits.append(str(digit)) # Return the final code return "".join(digits)