Write a C program to find the roots of a quadratic equation

In this article, we will write a C program to find the roots of a quadratic equation.


ALGORITHM: 

Step 1: Start 

Step 2: Read a,b,c 

Step 3: calculate disc = b*b-4*a*c 

Step 4: if(disc>0) Begin 

Step 5: root1=(-b+sqrt(disc))/(2*a) 

Step 6: root2=(-b-sqrt(disc))/(2*a) 

Step 7: Print “Root1” , “Root2” End 

Step 8: else if(disc=0) Begin 

Step 9: root1=-b/(2*a) 

Step 10: root2=root1; 

Step 11: Print “Root1” , “Root2” End 

Step 12: else 

Step 13: Print Roots are imaginary 

Step 14: Stop 

Write a C program to find the roots of a quadratic equation

#include <stdio.h> #include <conio.h> #include <math.h> int main() {	int a, b, c;	float disc, root1, root2;	float img, real;	printf("ENTER VALUES FOR a,b,c:\n");	scanf("%d%d%d", &a, &b, &c);	disc = (float) b *b - 4 *a * c;	if (disc > 0)	{	printf("THE ROOTS ARE REAL &UNEQUAL:\n");	root1 = (-b + sqrt(disc)) / (2 *a);	root2 = (-b - sqrt(disc)) / (2 *a);	printf("Root1=%f\n", root1);	printf("Root2=%f\n", root2);	}	else if (disc == 0)	{	printf("THE ROOTS ARE REAL AND EQUAL:\n");	root1 = -b / (2 *a);	root2 = root1;	printf("Root1=%f\n", root1);	printf("Root2=%f\n", root2);	}	else	{	printf("THE ROOTS ARE IMAGINARY:\n");	disc = -disc;	img = (float) disc / 2 * a;	real = (float) - b / 2 * a;	if (img > 0)	{	printf("Root1=%f + i%f\n", real, img);	printf("Root2=%f - i%f\n", real, img);	}	else	{	img = -img;	printf("Root1=%f + i%f\n", real, img);	printf("Root2=%f - i%f\n", real, img);	}	}	return 0; }

INPUT:

ENTER VALUES FOR a,b,c 1 4 4

OUTPUT:

THE ROOTS ARE EQUAL AND THEY ARE.. Root1=-2 Root2=-2

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