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80 votes

Is there any deep philosophy or intuition behind the similarity between $\pi/4$ and $e^{-\gamma}$?

The intuition may be helped by considering the generalized Euler constant function $$\gamma(z)=\sum_{n=1}^\infty z^{n-1}\left(\frac{1}{n}-\ln\frac{n+1}{n}\right),\;\;|z|\leq 1.$$ Its values include ...
Carlo Beenakker's user avatar
37 votes
Accepted

Is the integral of $e^{-x^2}$ from $0$ to $1$ known to be irrational?

Following @te4's comment, we can look at the function $$f(x) = \frac{\sqrt{\pi}}{2\sqrt x} \operatorname{erf}(\sqrt{x}) = \sum_{n=0}^\infty \frac{(-1)^n x^n}{(2n+1) n!}.$$ Note that it's an E-function,...
Daniel Weber's user avatar
  • 4,868
32 votes
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What is this modified arithmetico-geometric mean function?

The function $A(x,y)$ has the closed-form expression $$A(x,y)=\frac{\sqrt{y^2-x^2}}{\arccos(x/y)}.$$ This modification of the AGM was introduced by Gauss in 1800, in an unpublished letter. It was ...
Carlo Beenakker's user avatar
27 votes
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What is the value of $j(2\sqrt{-163})$?

The minimal polynomial is ...
Noam D. Elkies's user avatar
25 votes
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Representations of $\zeta(3)$ as continued fractions involving cubic polynomials

See NOTE below. This MO inquiry is over 3 yrs old now. By the date the question about the $\zeta(3)$ CF with $k=8/7$ was made (Feb, 2019), it can be answered in the negative nowadays, since it was '(...
Jorge Zuniga's user avatar
  • 3,271
23 votes

Is the integral of $e^{-x^2}$ from $0$ to $1$ known to be irrational?

$\newcommand{\Q}{\mathbb Q}\newcommand{\erf}{\operatorname{erf}}$(This answer had been posted before I saw Command Master's answer. I am leaving it here, since it contains more and/or different ...
Iosif Pinelis's user avatar
22 votes

A new way of approaching the pole of the Riemann zeta function - and a new conjectured formula

The paper entitled Euler constant as a renormalized value of Riemann zeta function at its pole by Andrei Vieru contains a derivation of the first formula in the OP (Benoȋt Cloitre's formula), and ...
Carlo Beenakker's user avatar
22 votes

Closed form of an infinite series

Denote $c_n:={(-1)^n \frac{\Gamma(\frac{1}{3}+\frac{n}{3})}{\Gamma(1+\frac{n}{3})} \sin(\frac{2\pi n}{3})}$ the $n$-th term of the series. We have for all $k\ge0$ $$c_{3k}=0,$$ $$c_{3k+1}= (-1)^{k+1}\...
Pietro Majer's user avatar
  • 63.5k
18 votes
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Is there a specific named function that is the inverse of $x+x^a$ for $x$ real?

The answer is yes indeed. It is a special case of Fox-H function, a variation of the confluent Fox-Wright $_{1}\Psi_{1}$ function (a generalization of the confluent hypergeometric function $_{1}F_{1}$)...
Jorge Zuniga's user avatar
  • 3,271
18 votes

Power series $x^n/n$ with one plus, then two minuses, then three plusses, and so on

The answer is in terms of theta functions. Let $$\Psi(q)=1+q+q^3+q^6+q^{10}+q^{15}+\cdots;$$ this is a Jacobi theta function that can be written as $q^{-1/8}\eta^2(2\tau)/\eta(\tau)$ where $q=e^{2\pi ...
Dave Benson's user avatar
  • 22.4k
17 votes
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Any name for this special function?

This is a standard hypergeometric function. Note that $$ \frac{1}{(a-m)!} = (-1)^m \frac{(-a)_m}{a!}\quad\text{and}\quad \frac{1}{(b+m)!} = \frac{1}{b!\,(b+1)_m}$$ in terms of the rising Pochhammer ...
Timothy Budd's user avatar
  • 4,002
17 votes

Why does this theta function value yield such a good Riemann sum approximation?

This is because the theta function has a functional equation. Under the usual definition $\theta(t) = \sum_n e^{-\pi t n^2}$, the functional equation is $$\theta(t) = \frac 1{\sqrt t} \theta\left(\...
WhatsUp's user avatar
  • 3,472
16 votes

A new way of approaching the pole of the Riemann zeta function - and a new conjectured formula

The first formula is trivial. $$f(s)= \frac1{s-1}+\gamma +O(s-1)$$ $$g(z)=1+2^{-z}+3^{-z}+4^{-z}+O(5^{-z})=1+2^{-z}(1+(3/2)^{-z}+(4/2)^{-z}+O(5/2)^{-z})$$ $$f(g(z)) = \frac1{2^{-z}(1+(3/2)^{-z}+(4/2)^...
reuns's user avatar
  • 3,434
16 votes
Accepted

Question about functions $f: \mathbb{Z}^+ \to \mathbb{Z}^+$ such that $x$ is prime whenever $f(x)$ is prime

As observed in comments, we have $f(n) = \lfloor g(n) \rfloor$ where $g(n) = \frac{\alpha^n + \alpha^{-n}}{4}$ and $\alpha = 2 + \sqrt{3}$. From the recurrence $g(n+1) = 4 g(n) - g(n-1)$ we see that $...
Terry Tao's user avatar
  • 120k
15 votes
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Short research articles

[a bit too long for a comment] I understand from the question that the aim is to find a research project based on the search for a counterexample. By construction, this will mean showing that some ...
15 votes
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Origins of the Bessel function (particularly of the 1st kind)

The story is explained in detail in the first chapter of the book: G. N. Watson, Treatise on the theory of Bessel functions, Cambridge, 1922. A Riccati equation $y'=y^2+x^2$ first appears in the work ...
Alexandre Eremenko's user avatar
14 votes
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Several conjectured identities for polylogarithms

(Updated answer): Upon further research, it turns out your three equations involving $\phi$ are special cases of three polylogarithm ladders of index $12,\,20,\,24$ that can be found in "The ...
Tito Piezas III's user avatar
14 votes
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Series involving factorials

The sum $$\sum_{k=0}^\infty \frac{(a+k)!\,(b+k)!}{k!\,(a+b+c+k+1)!}z^k.$$ is not only a generalized hypergeometric series; it's the original ungeneralized Gauss hypergeometric series, $$\frac{\Gamma(a+...
Ira Gessel's user avatar
  • 17.7k
14 votes
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A surprising identity: $\det[\cos\pi\frac{jk}n]_{1\le j,k\le n}=(-1)^{\lfloor\frac{n+1}2\rfloor}(n/2)^{(n-1)/2}$

First of all, we use the formula $$ D:=\det [x_j^k+x_j^{-k}]_{j,k=0,\dots,m-1}=\prod_{l<j}(x_j+x_j^{-1}-x_l-x_l^{-1})=\prod_{l<j} (x_j-x_l)(1-x_j^{-1}x_l^{-1}). $$ This follows from the ...
Fedor Petrov's user avatar
14 votes

A new formula for the class number of the quadratic field $\mathbb Q(\sqrt{(-1)^{(p-1)/2}p})$?

If by "the class number $h(p^*)$ of the quadratic field $\mathbb{Q}(\sqrt{p^*})$" you mean "the minus class number $h^{-}$ of $\mathbf{Q}(\zeta_p)$" and if by " a possible new formula for the ...
user134696's user avatar
14 votes
Accepted

A multiple integral that seems related to the $\zeta$ function at even integers

We have $$I_{2n}=\frac{(2n)!!}{(2n+1)!!}\cdot \frac1{2n+2}\cdot \pi^{2n}.$$ To see this, we follow the suggestion by Terry Tao in the comments and apply the diagonalization of the integral operator ...
Fedor Petrov's user avatar
14 votes
Accepted

Why does this theta function value yield such a good Riemann sum approximation?

I would give a slightly more direct explanation than WhatsUp. The Poisson summation formula states that for $f$ a smooth rapidly decreasing function on $\mathbb R$, $\hat{f}$ the Fourier transform, ...
Will Sawin's user avatar
  • 162k
13 votes

A new formula for the class number of the quadratic field $\mathbb Q(\sqrt{(-1)^{(p-1)/2}p})$?

The conjecture is not true, as some examples show. Let $D(p)$ denote your number. For primes $p \equiv 1 \textrm{ mod } 4$, we have $D(29)=8$, $D(37)=37$, $D(41)=121$ while $h(29)=h(37)=h(41)=1$. ...
François Brunault's user avatar
13 votes
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Speed of convergence of $\zeta(2k)\to 1$?

Here is an explicit bound. The sum $\sum_{n > N} n^{-s}$ for real $s > 1$ is bounded by the integral $$\int_N^\infty x^{-s} = N^{1-s} / (s-1).$$ Therefore for any $N$ you have $$0 < \zeta(s) -...
Sean Eberhard's user avatar
13 votes
Accepted

Is the Gauss hypergeometric series ${}_2F_1\bigl(\frac{1}{2},\frac{1}{2};2;t\bigr)$ an elementary function?

Maple does it in terms of complete elliptic integrals $\rm{K}$ and $\rm{E}$ ... $$ {\mbox{$_2$F$_1$}\left(\frac12,\frac12;\,2;\,t\right)}={\frac {4\left( t-1 \right){\rm K} \left( \sqrt {t} \right) ...
Gerald Edgar's user avatar
  • 41.7k
13 votes
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Riemann, fluid dynamics, and critical lines

Q: Does anyone know of a reference which discusses more thoroughly the critical line appearing in Riemann's hydrodynamics problem? A: A recent reference is Elliptical instability in hot Jupiter ...
Carlo Beenakker's user avatar
13 votes
Accepted

Conjectured closed form of $\int_0^1 \frac{\text{Li}_2\left(\frac{x}{4}\right)}{4-x}\,\log\left(\frac{1+\sqrt{1-x}}{1-\sqrt{1-x}}\right)\,dx$

As Henri Cohen remarked, the identity to prove is equivalent to $$\sum_{n=1}^\infty \frac{H_n^{(2)}}{(n+1)(2n+1)\binom{2n}{n}}=\frac{\pi^4}{972}.\tag{1}$$ In turn, this follows readily from the OP's ...
GH from MO's user avatar
  • 114k
13 votes
Accepted

Missing factor of 10 in derivation for integral form of ζ(3)

It is $-5\zeta(3)$. Moreover, we have separately (1) $\int \frac{\log(1-xy)}{xy}=-\zeta(3)$ and (2) $\int \frac{\log(1-\sqrt{xy})}{xy}=-4\zeta(3)$. For proving (1), expand the log as a Taylor series ...
Fedor Petrov's user avatar
13 votes
Accepted

Proving identity involving dilogarithms and $\pi/9$

1. I believe that the first (and perhaps only) published proof of this identity appears in Kirillov's 1995 paper Dilogarithm identities. This paper was also pointed out by Carlo Beenakker in his (...
GH from MO's user avatar
  • 114k
12 votes
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Evaluating elliptic integrals

This question has been out for a while, and I think it deserves a thorough answer, even tho I came quite late to this party. As both the classical Legendre-Jacobi theory and the Carlson theory have ...
J. M. isn't a mathematician's user avatar

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