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54 votes
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The "square root" of a graph?

There is a fixed-point-free involution on these graphs which I will call loop-switching, given by adding a loop to every vertex that doesn't have one while simultaneously deleting the loops from all ...
lambda's user avatar
  • 1,432
40 votes

The "square root" of a graph?

These numbers count balanced signed graphs (without loops). A signed graph is a graph in which every edge has a sign, either positive or negative. It is balanced if every cycle has an even number of ...
Ira Gessel's user avatar
  • 17.7k
22 votes
Accepted

How to prove the identity $\sum_{k=0}^\infty(22k^2-92k+11)\binom{4k}k/16^k=-5$?

Per my old answer in AoPS, the generating function $f(x) := \sum_{k\geq0} \binom{4k}k x^k$ satisfies the algebraic identity: $$(f(x) - 1)(3f(x) + 1)^3 = x ( 4 f(x) )^4.$$ From where by differentiating,...
Max Alekseyev's user avatar
22 votes

Have you seen my power series?

The general solution to $$\Phi(q,t)\cdot \Phi(q^{-1},-t) = 1,\quad \Phi(q,0)=-1$$ is given by $$\Phi(q,t)=-e^{tF(q+q^{-1},t^2) + (q-q^{-1})t^2G(q+q^{-1},t^2)},$$ where $F$ and $G$ are arbitrary ...
Max Alekseyev's user avatar
21 votes
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Alternating sum of hook lengths: Part I

The hook length $h_{ij}(\lambda)$ counts the number of boxes directly below or directly to the right of box $(i,j)$. (I picture the Young diagram of $\lambda$ as having the corner $(0,0)$ located in ...
Gjergji Zaimi's user avatar
19 votes
Accepted

Coincidence between coefficients of tanh(tan(x/2)) and Chow ring computations?

The integrals $$\int_{\overline{\mathcal{M}}_g} \lambda_{g-1}^3=\frac{|B_{2g}|}{2g}\frac{|B_{2g-2}|}{2g-2}\frac{1}{(2g-2)!}$$ were computed by Faber and Pandharipande in Theorem 4 in their paper Hodge ...
Samir Canning's user avatar
16 votes

Generating function in graph theory

Consider all trees with labelled vertices $1,\dots,n$, for each tree take a monomial $\prod_{i=1}^n x_i^{\deg(i)-1}$. The sum $F_n$ of these monomials equals $(\sum x_i)^{n-2}$. This may be proved by ...
Fedor Petrov's user avatar
16 votes
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Non-enumerative proof that, in average, less than 50% of tiles in domino tiling of 2-by-n rectangle are vertical?

Here is at least a heuristic argument for why we should expect fewer vertical dominoes than horizontal dominoes. As we increase the length of the strip (to the right, say), let us think about how the ...
Timothy Chow's user avatar
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16 votes
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Matrices of combinatorial sequences that are inverse in two ways

Following up on David's nice answer, there is a different parametrization that makes the pattern much more obvious. Namely, let $s_1,s_2,\dots$ be arbitrary, then you can write $$A=\Big(h_{i-j}(s_1,...
Gjergji Zaimi's user avatar
15 votes

A special type of generating function for Fibonacci

Sure: choose any nonzero value for $a_0$, and write $F(x)=a_0+a_1x+a_2x^2+...$. Expanding $F(x)^n$ gives you a LINEAR equation in $a_n$ as a function of the preceding ones, the coefficient of $a_n$ ...
Henri Cohen's user avatar
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15 votes
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Generating function for Schur polynomials

This is done in my paper The character generator of SU(n). I believe there was an essentially the same previous MO question, but I am unable to find it.
Richard Stanley's user avatar
15 votes
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How are Sheffer polynomials related to Lie theory?

First, a general set of Sheffer polynomials is not orthogonal with respect to some weight function; for example, the prototypical sequence $p_n(x) = x^n$, which belongs to both special sub-groups of ...
Tom Copeland's user avatar
15 votes

Recursion for generating functions

That seems really unlikely. For example, $$F(z)=\sum_{k=0}^\infty 2^kz^k = \frac{1}{1-2z}$$ is a rational function, but $$G(z)=\sum_{k=0}^\infty 2^{2^k}z^k$$ has radius of convergence $0$.
Gerald Edgar's user avatar
  • 41.7k
14 votes
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Congruences Ramanujan-style

More general versions of this have been established: see in particular Theorem 2 of Kiming and Olsson, and for other work see (for example) Locus and Wagner. To answer the question fully, as Ofir ...
Lucia's user avatar
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14 votes
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Properties of some polynomials defined by $P_{n}(x)={e}^{-x}\sum_{k=0}^{\infty}\frac{a_{k,n}{x}^{k}}{k!}$

Noticing that $$a_{k,n} = \frac1{\prod_{i=1}^n (k+2i)} = \frac1{2^n(n-1)!}\int_0^1 (1-t)^{n-1}t^{k/2}\,{\rm d}t,$$ we get $$P_n(x) = \frac{e^{-x}}{2^n(n-1)!} \int_0^1 (1-t)^{n-1} e^{x\sqrt{t}}\,{\rm d}...
Max Alekseyev's user avatar
13 votes

Important combinatorial and algebraic interpretations of the coefficients in the polynomial $[n]!_q = (1+q)(1+q+q^2) \ldots (1+q+\cdots + q^{n-1})$

This answer concerns a geometric/Lie-theoretic interpretation of $[n]!_q$. Suppose that $q=p^k$ is a prime power. Then $[n]!_q$ is the number of points in the full flag variety of full flags of ...
13 votes
Accepted

Is the Gauss hypergeometric series ${}_2F_1\bigl(\frac{1}{2},\frac{1}{2};2;t\bigr)$ an elementary function?

Maple does it in terms of complete elliptic integrals $\rm{K}$ and $\rm{E}$ ... $$ {\mbox{$_2$F$_1$}\left(\frac12,\frac12;\,2;\,t\right)}={\frac {4\left( t-1 \right){\rm K} \left( \sqrt {t} \right) ...
Gerald Edgar's user avatar
  • 41.7k
13 votes
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Finding $\sum_i x_i$ given $\{\sum_i x_i^{2n}\}_{n\in \mathbb{N}}$

If you plot $\log f_n$ versus $n$, with $f_n=\sum_i x_i^{2n}$, then the asymptotic slope for large $n$ will give you the largest of the $x_i$; subtracting that contribution from $f_n$ and repeating ...
Carlo Beenakker's user avatar
12 votes
Accepted

Why $\lim_{n\rightarrow \infty}\frac{F(n,n)}{F(n-1,n-1)} =\frac{9}{8}$?

We will compute the generating function, and use the method described in section 2 of this paper. Let $F_{m,n}=F(m,n)$. Consider the generating function $$G(x,y)=\sum_{m=0}^\infty\sum_{n=0}^\infty F_{...
Thomas Browning's user avatar
12 votes

Series involving power of the index

There are many ways to prove the formula $$ \sum_{n=1}^{\infty} \frac{n^{n-1}}{n!}(xe^{-x})^n = x.\tag{1}$$ As Alexandre Eremenko noted, one approach is Lagrange inversion. Another can be found at ...
Ira Gessel's user avatar
  • 17.7k
12 votes
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Generating function for A261041

Let us derive a formula for $a(n)$. We will employ the inclusion-exclusion principle to get $a(n)$ as the number of partitions not satisfying any of the properties $P_i =$ "elements $i$ and $i+1$ ...
Max Alekseyev's user avatar
11 votes

Generating function in graph theory

A good source (despite not being very modern) is Harary, Palmer - Graphical enumeration. A few examples: let $C(x) = \sum_{n = 0}^{\infty} x^n \frac{2^{n(n - 1) / 2}}{n!}$ be the e.g.f. of labelled ...
Mikhail Tikhomirov's user avatar
11 votes

A special type of generating function for Fibonacci

Lagrange–Bürmann formula claims that $$[w^{n-1}]H'(w)(\varphi(w))^n=n[z^n]H(g(z)),$$ where $g(z)$ and $f(w)=w/\varphi(w)$ are compositionally inverse power series without constant term (that is $g(f(w)...
Fedor Petrov's user avatar
11 votes

A special type of generating function for Fibonacci

Another way to state Fedor's answer is Exercise 5.56(a) of Enumerative Combinatorics, vol. 2. Namely, if $G(x)=a_1x+a_2x^2+\cdots$ is a power series (say over $\mathbb{C}$) with $a_1\neq 0$ and $n>...
Richard Stanley's user avatar
11 votes

Matrices of combinatorial sequences that are inverse in two ways

I don't know, but I will point out that, if you specify the entries $A_{(i+1)i}$, then every other entry is uniquely determined by these. The property of being inverse as matrices means that the upper ...
David E Speyer's user avatar
11 votes

Finding $\sum_i x_i$ given $\{\sum_i x_i^{2n}\}_{n\in \mathbb{N}}$

If $\sum x_i^2$ is finite, the sum $f(z)=\sum \frac{x_i^2}{1-x_i^2z}$ is a meromorphic function on the complex plane, and we know its Taylor series at 0. Thus we know $f$, hence the poles of $f$, ...
Fedor Petrov's user avatar
11 votes
Accepted

Reference request: Gessel interview's generating function identities

Result 1 can be found in N. G. de Bruijn, Asymptotic Methods in Analysis, Dover, New York, 1981, p. 71. Result 2 follows from a formula of E. M. Wright, though he didn't state it in this form. A ...
Ira Gessel's user avatar
  • 17.7k
11 votes

Have you seen my power series?

In most situations I know, the equation $$ \Phi(q,t)\Psi(q^{-1},-t)=1 $$ indicates that there is a Koszul algebra $A$ with the "standard" grading $A=\bigoplus_n A_n$ (for which Koszulness ...
Vladimir Dotsenko's user avatar
11 votes

Have you seen my power series?

Not an answer, but a conjecture. Based on numerical evidence, I would like to venture the conjecture that there is an infinite product formula $$\Psi(q,t) = −\Phi(q,−t) = \frac{1}{\displaystyle\prod_{...
Balazs's user avatar
  • 3,497

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