Advent of Code 2021 Python Solution: Day 10

data,data1=get_data(day=10) table = { ")": 3, "]": 57, "}": 1197, ">": 25137} pair = {"(":")","{":"}", "[":"]", "<":">"} corruptions = [] rem = [] for i,r in enumerate(data): stack = [] is_corr=False for c in r: if c in pair: stack.append(pair[c]) elif stack.pop() != c: print(f"Corrupted {c} at row {i}") corruptions.append(c) is_corr=True break if is_corr==False and len(stack)>0: rem.append(stack) corr = dict(Counter(corruptions)) sum([table[k]*v for k,v in corr.items()]) 

mult = {")": 1, "]": 2, "}": 3, ">": 4} all_total=[] for row in rem: s = 0 for i,c in enumerate(row): s+=5**i*mult[c] all_total.append(s) at = sorted(all_total) at[len(at)//2]