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Prashant Mishra
Prashant Mishra

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Inorder traversal of a binary tree

Problem

In inorder traversal of a binary tree, we visit left node then root and finally the right node.

/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */ class Solution { public List<Integer> inorderTraversal(TreeNode root) { List<Integer> list = new ArrayList<>(); inorder(root,list); return list; } public void inorder(TreeNode node, List<Integer> list){ if(node ==null) return; inorder(node.left,list); list.add(node.val); inorder(node.right,list); } } 
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