C# Program to get the smallest and largest element from a list

Set a list.

List<long> list = new List<long> { 150, 300, 400, 350, 450, 550, 600 };

To get the smallest element, use the Min() method.

list.AsQueryable().Min();

To get the largest element, use the Max() method.

list.AsQueryable().Max();

Let us see the complete code −

Example

 Live Demo

using System; using System.Collections.Generic; using System.Linq; class Demo {    static void Main() {       List<long> list = new List<long> { 150, 300, 400, 350, 450, 550, 600 };       foreach(long ele in list){          Console.WriteLine(ele);       }       // getting largest element       long max_num = list.AsQueryable().Max();       // getting smallest element       long min_num = list.AsQueryable().Min();       Console.WriteLine("Smallest number = {0}", min_num);       Console.WriteLine("Largest number = {0}", max_num);    } }

Output

150 300 400 350 450 550 600 Smallest number = 150 Largest number = 600