C# program to find Largest, Smallest, Second Largest, Second Smallest in a List

Set the list

var val = new int[] {    99,    35,    26,    87 };

Now get the largest number.

val.Max(z => z);

Smallest number

val.Min(z => z);

Second largest number

val.OrderByDescending(z => z).Skip(1).First();

Second smallest number

val.OrderBy(z => z).Skip(1).First();

The following is the code −

Example

 Live Demo

using System; using System.Linq; public class Program {    public static void Main() {       var val = new int[] {          99,          35,          26,          87       };       var maxNum = val.Max(z => z);       Console.WriteLine("Maximum Number: " + maxNum);       var minNum = val.Min(z => z);       Console.WriteLine("Minimum Number: " + minNum);       var secondMax = val.OrderByDescending(z => z).Skip(1).First();       Console.WriteLine("Second Largest Number: " + secondMax);       var secondMin = val.OrderBy(z => z).Skip(1).First();       Console.WriteLine("Second Smallest Number: " + secondMin);    } }

Output

Maximum Number: 99 Minimum Number: 26 Second Largest Number: 87 Second Smallest Number: 35