Java Program to Find Transpose of a Matrix

To understand this example, you should have the knowledge of the following Java programming topics:


Transpose of a matrix is the process of swapping the rows to columns. For 2x3 matrix,

 Matrix a11 a12 a13 a21 a22 a23 Transposed Matrix a11 a21 a12 a22 a13 a23

Example: Program to Find Transpose of a Matrix

 public class Transpose { public static void main(String[] args) { int row = 2, column = 3; int[][] matrix = { {2, 3, 4}, {5, 6, 4} }; // Display current matrix display(matrix); // Transpose the matrix int[][] transpose = new int[column][row]; for(int i = 0; i < row; i++) { for (int j = 0; j < column; j++) { transpose[j][i] = matrix[i][j]; } } // Display transposed matrix display(transpose); } public static void display(int[][] matrix) { System.out.println("The matrix is: "); for(int[] row : matrix) { for (int column : row) { System.out.print(column + " "); } System.out.println(); } } }

Output

 The matrix is: 2 3 4 5 6 4 The matrix is: 2 5 3 6 4 4 

In the above program, display() function is only used to print the contents of a matrix to the screen.

Here, the given matrix is of form 2x3, i.e. row = 2 and column = 3.

For the transposed matrix, we change the order of transposed to 3x2, i.e. row = 3 and column = 2. So, we have transpose = int[column][row]

The transpose of the matrix is calculated by simply swapping columns to rows:

 transpose[j][i] = matrix[i][j];
Did you find this article helpful?

Your builder path starts here. Builders don't just know how to code, they create solutions that matter.

Escape tutorial hell and ship real projects.

Try Programiz PRO
  • Real-World Projects
  • On-Demand Learning
  • AI Mentor
  • Builder Community