C++ Programming Default Arguments (Parameters)

In C++ programming, we can provide default values for function parameters.

If a function with default arguments is called without passing arguments, then the default parameters are used.

However, if arguments are passed while calling the function, the default arguments are ignored.

Working of default arguments

We can understand the working of default arguments from the image above:

1. When temp() is called, both the default parameters are used by the function.
2. When temp(6) is called, the first argument becomes 6 while the default value is used for the second parameter.
3. When temp(6, -2.3) is called, both the default parameters are overridden, resulting in i = 6 and f = -2.3.
4. When temp(3.4) is passed, the function behaves in an undesired way because the second argument cannot be passed without passing the first argument.
   
   Therefore, 3.4 is passed as the first argument. Since the first argument has been defined as int, the value that is actually passed is 3.

Example: Default Argument

 #include <iostream> using namespace std; // defining the default arguments void display(char = '*', int = 3); int main() { int count = 5; cout << "No argument passed: "; // *, 3 will be parameters display(); cout << "First argument passed: "; // #, 3 will be parameters display('#'); cout << "Both arguments passed: "; // $, 5 will be parameters display('$', count); return 0; } void display(char c, int count) { for(int i = 1; i <= count; ++i) { cout << c; } cout << endl; }

Output

 No argument passed: *** First argument passed: ### Both arguments passed: $$$$$

Here is how this program works:

1. display() is called without passing any arguments. In this case, display() uses both the default parameters c = '*' and n = 1.
2. display('#') is called with only one argument. In this case, the first becomes '#'. The second default parameter n = 1 is retained.
3. display('#', count) is called with both arguments. In this case, default arguments are not used.

We can also define the default parameters in the function definition itself. The program below is equivalent to the one above.

 #include <iostream> using namespace std; // defining the default arguments void display(char c = '*', int count = 3) { for(int i = 1; i <= count; ++i) { cout << c; } cout << endl; } int main() { int count = 5; cout << "No argument passed: "; // *, 3 will be parameters display(); cout << "First argument passed: "; // #, 3 will be parameters display('#'); cout << "Both argument passed: "; // $, 5 will be parameters display('$', count); return 0; }

Things to Remember

1. Once we provide a default value for a parameter, all subsequent parameters must also have default values. For example,

    // Invalid void add(int a, int b = 3, int c, int d); // Invalid void add(int a, int b = 3, int c, int d = 4); // Valid void add(int a, int c, int b = 3, int d = 4);

2. If we are defining the default arguments in the function definition instead of the function prototype, then the function must be defined before the function call.

    // Invalid code int main() { // function call display(); } void display(char c = '*', int count = 5) { // code }

Also Read:

• C++ User-defined Function Types