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Project Utilities e UtilitiesTest Switch to file-scoped namespaces #435

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Merged
siriak merged 1 commit into from
Jan 9, 2024
Merged

Project Utilities e UtilitiesTest Switch to file-scoped namespaces #435

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43 changes: 21 additions & 22 deletions Utilities.Tests/Extensions/DictionaryExtensionsTests.cs
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Original file line number Diff line number Diff line change
@@ -1,37 +1,36 @@
using System;
using System;
using System.Collections.Generic;
using FluentAssertions;
using NUnit.Framework;
using Utilities.Extensions;

namespace Utilities.Tests.Extensions
namespace Utilities.Tests.Extensions;

public class DictionaryExtensionsTests
{
public class DictionaryExtensionsTests
[Test]
public void AddMany_ShouldThrowArgumentException_WhenKeyAlreadyExists()
{
[Test]
public void AddMany_ShouldThrowArgumentException_WhenKeyAlreadyExists()
{
var dictionary = new Dictionary<string, int> { ["one"] = 1 };
var enumerable = new[] { ("one", 1), ("two", 2) };
var dictionary = new Dictionary<string, int> { ["one"] = 1 };
var enumerable = new[] { ("one", 1), ("two", 2) };

var action = () => dictionary.AddMany(enumerable);
var action = () => dictionary.AddMany(enumerable);

action.Should().Throw<ArgumentException>();
}
action.Should().Throw<ArgumentException>();
}

[Test]
public void AddMany_ShouldAddAllKeyValuePairs()
{
var dictionary = new Dictionary<string, int> { ["one"] = 1 };
var enumerable = new[] { ("two", 2), ("three", 3) };
[Test]
public void AddMany_ShouldAddAllKeyValuePairs()
{
var dictionary = new Dictionary<string, int> { ["one"] = 1 };
var enumerable = new[] { ("two", 2), ("three", 3) };

dictionary.AddMany(enumerable);
dictionary.AddMany(enumerable);

dictionary.Should().HaveCount(3);
dictionary.Should().HaveCount(3);

dictionary.Should().ContainKey("one").WhichValue.Should().Be(1);
dictionary.Should().ContainKey("two").WhichValue.Should().Be(2);
dictionary.Should().ContainKey("three").WhichValue.Should().Be(3);
}
dictionary.Should().ContainKey("one").WhichValue.Should().Be(1);
dictionary.Should().ContainKey("two").WhichValue.Should().Be(2);
dictionary.Should().ContainKey("three").WhichValue.Should().Be(3);
}
}
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