Is there a (simple) way to feed variable with end of lines to other program in BASH? Consider example:
flist=$(ls -l) echo $flist echo will replace all end of lines with spaces, so my output will be different from the content of the variable. Other example:
echo $flist | grep myfile.txt This command will not work as expected to output only information about myfile.txt. How do I print the line that contains myfile.txt.
Here is one solution:
cat << EOF | grep myfile.txt $flist EOF Anything less ugly?
