HOW Check Url Parametr and Redirect with Nginx rewrite

Question

I want to check if a parameter is present in a url in nginx and then rewrite.

How can i do that?

my code is here and not work !

if ($arg_loc != "") { rewrite ^(/search/.*)$ $1? permanent; }

UPDATE : i want redirect any url that ends with loc=number to the parent url ! for arabic and enlgish characters

EG :

http://website.com/search/node/item123/loc=33

i want redirect to

http://website.com/search/node/item123/

or

http://website.com/search/node/عربیک/loc=55

should be :

http://website.com/search/node/عربیک

Your example URL has no query arguments, therefore your if code cannot work. — Tero Kilkanen
– Tero Kilkanen, Commented Nov 10, 2023 at 21:49
Please clarify your issue. Does the URL you want to redirect contain query arguments or not? If it has query arguments, then your if approach is correct. If not, then you need to match on the URL path. — Tero Kilkanen
– Tero Kilkanen, Commented Nov 11, 2023 at 17:49

Alexey Ten · Accepted Answer · 2023-11-12 18:27:58Z

1

There is no query parameters in your examples. It's just an url, so you could use rewrite.

Something like that:

rewrite "^(/search/node/[^/]+)/loc=\d+$" $1 permanent;

P.S. I would strongly recommend to use keyword redirect instead of permanent until you're 1000% sure that redirect works as it should.

answered Nov 12, 2023 at 17:30

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