Conditional evaluation

[stsxbel]

Good day. Please tell me how to correctly compute with the condition? there is a code:

a1 = float(result1[0] * 0.1) b1 = float(row[2]) c1 = b1 - a1 print (f'{c1:.lf}')

How to make a condition if c = negative value, then write to the database, if positive, then use the formula:

с1 = b1 - 6553.5 - a1

and write the result to the database

[perfringo]

This is called conditional expression.

It would be good to be precise in your question. There is no c in your code. You have c1

c = c1 if c1 < 0 else b1 - 6553.5 - a1

[stsxbel]

Several expressions are counted, so each one identifies 1,2, etc.

[Gribouillis]

Several expressions are counted, so each one identifies 1,2, etc.

This question is 100% cryptic, but maybe it's just me...

[stsxbel]

It does not work for me like this:

 a1 = float(result1[0] * 0.1) b1 = float(row[2]) #row2- 1продукт silos1a = b1 - a1 if silos1a < 0 print ("Расход:"f'{silos1a:.1f}') else b1 - 6553.5 - a1 print ("Расход:"f'{silos1a:.1f}')

SyntaxError: invalid syntax

[snippsat]

It does not work for me like this:

There are several error here,should look a some tutorials as these errors are really basic.

a1 = float(0.1) b1 = float(3.4) silos1a = b1 - a1 if silos1a < 0: print(f'Расход: {silos1a:.1f}') elif b1 - 6553.5 - a1: # Should maybe do some stuff here print(f'Расход: {silos1a:.1f}')

Output:
Расход111: 3.3

[stsxbel]

It worked in this version:

a1 = float(140.2) b1 = float(6543.5) silos1a = b1 - a1 if silos1a > 0: print(f'Расход: {silos1a:.1f}') else: silos1a = b1 - 6553.5 - a1 print(f'Расход: {silos1a:.1f}')

[Gribouillis]

It seems that you inverted the condition implied by your first post! You could also try something like

>>> a1, b1 = 140.2, 6543.5 >>> silos1a = b1 - a1 - bool(b1 > a1) * 6553.5 >>> print(f'Расход: {silos1a:.1f}') Расход: -150.2

This amounts to using bool() as a programmatic version of the Iverson bracket used by mathematicians.