How can I get some arguments using argparse?

[Mike Ru]

I am using a module argparse. I need to get arguments and then do something. I can only one argument now, but I cannot get some arguments if an user types two arguments.

python demo.py -c work.txt

Now here is my code:

import sys, argparse def main(): parser = argparse.ArgumentParser(description="Process some ...") #parser.add_argument('-n', '--name', required=True, help="name of the user") parser.add_argument('-n', '--name', required=False, help="name of the user") parser.add_argument('-a', '--adress', required=False, help="name of the host") parser.add_argument('-c', '--copy', required=False, help="Copy a file into a server") args = vars(parser.parse_args()) #if args for x in args.values(): if x != None: print(x) main()

I can get them list_args like that:

python demo.py -a Russia -c work.txt

 args = vars(parser.parse_args()) list_args = [] for x in args.values(): if x != None: list_args.append(x) print(list_args)

but then I cannot understand where who is.
How to do it?

---

OMG! I resolved it.

import argparse def main(): parser = argparse.ArgumentParser(description="Process some ...") parser.add_argument('-n', '--name', required=False, help="name of the user") parser.add_argument('-a', '--adress', required=False, help="name of the host") parser.add_argument('-c', '--copy', required=False, help="Copy a file to the server") args = vars(parser.parse_args()) if args['name']: print('i am name {}'.format(args['name'])) if args['adress']: print('i am adress {}'.format(args['adress'])) if args['copy']: print('i am copy {}'.format(args['copy'])) main()