I am learning about lists and apparently list.count does not function in the following:

mylist = [5, 12, 27, 3, 12, 5, 9, 5, 11] mylist.count(3) print(mylist)

The output I get is

Output:
[5, 12, 27, 3, 12, 5, 9, 5, 11]

whereas it should return 1
When I use .insert, .reverse, .extend all is well!

Am I likely to have a problem with the Python package I am using?

I am using Windows 10 and Python 3.9.2

Any help would be appreciated

It is working good to me,

mylist = [5, 12, 27, 3, 12, 5, 9, 5, 11] print(mylist.count(5)) print(mylist.count(3)) print(mylist) k=mylist.count(12) print(k)

Output:
C:\Users\sandeep\Downloads>py test.py 3 1 [5, 12, 27, 3, 12, 5, 9, 5, 11] 2

Best Regards,
Sandeep.

GANGA SANDEEP KUMAR

mylist = [5, 12, 27, 3, 12, 5, 9, 5, 11] print(mylist.count(3)) # Need print() print(mylist)

Output:
1 [5, 12, 27, 3, 12, 5, 9, 5, 11]

mylist = [5, 12, 27, 3, 12, 5, 9, 5, 11] count_number = 5 result = mylist.count(count_number) print(f'There where {result} occurrences of <{count_number}> in:\n{mylist}')

Output:
There where 3 occurrences of <5> in: [5, 12, 27, 3, 12, 5, 9, 5, 11]

It is important that you understand that there are methods that work in-place (and return None) and others that return something like in this case - list.count() will return the result (if you want to use it, you need to bind it to a name, or print it, etc.)

Thank you Sandeep_ganga, snippsat & Buran.
I get that - I was not using the print statement correctly not recognising I had called up print the original list and not the count result. However if I use mylist.reverse I have to revert to the my initial way of working as belowL

mylist = [5, 12, 27, 3, 12, 5, 9, 5, 11] mylist.reverse() print(mylist)

which gives the correct output of

Output:
[11, 5, 9, 5, 12, 3, 27, 12, 5]

Is this because I am using () in the call and not specifying anything between ()?

Thanks

(Mar-16-2021, 01:42 PM)Oldman45 Wrote: Is this because I am using () in the call and not specifying anything between ()?

no, it is because .reverse() method works in-place.

(Mar-16-2021, 01:42 PM)Oldman45 Wrote: Is this because I am using () in the call and not specifying anything between ()?

No it's because reverse() is modifying the original list in place.
So in case can not store it in a variable.

>>> mylist = [5, 12, 27, 3, 12, 5, 9, 5, 11] >>> help(mylist.reverse) Help on built-in function reverse: reverse() method of builtins.list instance Reverse *IN PLACE*. >>> rev = mylist.reverse() >>> rev >>> repr(rev) 'None' >>> >>> mylist [11, 5, 9, 5, 12, 3, 27, 12, 5]

count() is different as it return the result that can be stored in variable.

>>> mylist [11, 5, 9, 5, 12, 3, 27, 12, 5] >>> mylist = [5, 12, 27, 3, 12, 5, 9, 5, 11] >>> help(mylist.count) Help on built-in function count: count(value, /) method of builtins.list instance Return number of occurrences of value. >>> c = mylist.count(5) >>> c 3 

Buran, snippsat thanks for the education, I will now practice what I learnt. I really appreciate the support