The equation of a line in slope-intercept form is given by
| (1) |
so the line has slope . Now consider the distance from a point
to the line. Points on the line have the vector coordinates
| (2) |
Therefore, the vector
| (3) |
is parallel to the line, and the vector
| (4) |
is perpendicular to it. Now, a vector from the point to the line is given by
| (5) |
Projecting onto
,
| (6) | |||
| (7) | |||
| (8) | |||
| (9) | |||
| (10) | |||
| (11) |
If the line is specified by two points and
, then a vector perpendicular to the line is given by
| (12) |
Let be a vector from the point
to the first point on the line
| (13) |
then the distance from to the line is again given by projecting
onto
, giving
| (14) |
As it must, this formula corresponds to the distance in the three-dimensional case
| (15) |
with all vectors having zero -components, and can be written in the slightly more concise form
| (16) |
where denotes a determinant.
The distance between a point with exact trilinear coordinates and a line
is
| (17) |
(Kimberling 1998, p. 31).