0
$\begingroup$

Let $f_\theta(x) = \exp(\theta T(x) - K(\theta))$ be a one-parameter exponential family of probability density functions with respect to the Lebesgue measure on $\mathbb{R}$, for $\theta$ in an open interval $\Theta$. Let $F_\theta(x)$ be the corresponding cumulative distribution function (CDF), and let $\Phi(z)$ be the CDF of the standard normal distribution $N(0,1)$.

I am interested in identifying conditions that $T$ and $K$ must satisfy in order for the normalizing transformation $g_\theta(x) := \Phi^{-1}(F_\theta(x))$ to be an elementary function of $x$ for all $\theta \in \Theta$. (Here, "elementary" is used in the sense of Liouville: functions built from constants, algebraic functions, exponentials, and logarithms through finite composition and arithmetic operations.)

Reformulation as a Differential Equation

The condition $\Phi(g_\theta(x)) = F_\theta(x)$ implies, by differentiation with respect to $x$, the following first-order nonlinear ordinary differential equation for $g_\theta(x)$: $$\phi(g_\theta(x)) \cdot g'_\theta(x) = f_\theta(x)$$ where $\phi(z) = (2\pi)^{-1/2} e^{-z^2/2}$ is the standard normal PDF. This can be rewritten as: $$g'_\theta(x) = \sqrt{2\pi} \exp\left(\theta T(x) - K(\theta) + \frac{1}{2} g_\theta(x)^2\right)$$ The problem is thereby equivalent to asking:

For which choices of the function $T(x)$ does this differential equation admit a solution $g_\theta(x)$ that is an elementary function of $x$ for every $\theta$?

The trivial case is the normal distribution itself, where $T(x)=x$ and $g_\theta(x)$ is linear in $x$. I am seeking non-trivial examples or, ideally, a complete characterization.


This question is motivated by an attempt to generalize the methods introduced in the paper "Bounds on Tail Probabilities in Exponential families."

$\endgroup$

0

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.