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Given a function $f(x) : \mathbb{R}^n \to \mathbb{R}$, we call it algebraic if it satisfies a polynomial equality $g(y, x) = 0$.

This is analogous to an algebraic number being the root of a univariate polynomial. A useful property of a set of algebraic numbers $\{a_i\}_1^m$ is that there exists an algebraic number $b$ such that each of $a_i$ can be expressed as a polynomial (with rational coefficients) in $b$. The number $b$ is called the primitive element.

This fact is a result of the primitive element theorem, which is typically expressed in more abstract algebra terms ("every finite separable field extension is simple, i.e. generated by a single element"). This is useful in computer algebra; for example to compute the rational lift of a polynomial with algebraic coefficients. Many computer algebra systems have algorithms that can compute the primitive element $b$ of a set of algebraic numbers, as well as the polynomial representation of each of the $a_i$.

Can we say something similar for algebraic functions? Are there algorithms that can find such a primitive element?

I'm interested in this for the purposes of solving optimization problems with algebraic objectives or constraints. If it was possible to compute such a primitive element, we could rewrite an algebraic optimization problem as a polynomial optimization problem, amenable to sum-of-squares programming (in the sense of e.g. Parrilo), by introducing a single new variable and a single new constraint (the primitive element and its minimal polynomial). (Although I haven't thought this idea out fully.)

I would appreciate any pointers to relevant references!

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    $\begingroup$ Is what you want essentially an element of the algebraic closure of the field $\mathbb{R}(X)$? $\endgroup$ Commented Aug 21, 2024 at 12:11
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    $\begingroup$ You can just apply the primitive element theorem to a finite extension of $\mathbb{R}(x)$. There are proofs that make this algorithmic, e.g. you can induct on the fact that if $\alpha, \beta$ are algebraic over $K$ then the set of $t \in K$ such that $\alpha + t \beta$ is not a primitive element of $K(\alpha, \beta)$ is the set of roots of a polynomial you can explicitly compute, and in particular there are finitely many such $t$. $\endgroup$ Commented Aug 22, 2024 at 5:18

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