2
$\begingroup$

Let $f: \mathbb R_{+} \to \mathbb R_{+}$ be an $s$-function in the second sense, i.e., $$ f(\lambda x +(1-\lambda)y) \leq \lambda^s f(x) +(1-\lambda)^s f(y)$$ for every $\lambda \in (0,1)$. Assume further that, there exists a convex function $g: \mathbb R_{+} \to \mathbb R_{+}$ and $a< b \in \mathbb R_{+}$ such that $$ a g(x) \leq f(x) \leq b g(x).$$ Is it true that $f$ is also convex? Or any criterion so that $f$ is convex? One trivial example is $f$ should have the form $f= c g$ for $a\leq c \leq b$, but in general I cannot figure out any other condition for convexity.

$\endgroup$
0

0

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.