Unless I'm missing something, there is no way to add a type-hinted parameter to a method that does not use the fully-qualified name (as it exists as a use statement).

e.g. (See SomeClass type-hint in method)

use Foo\Bar\SomeClass; class GeneratedClass { public function generatedMethod(SomeClass $instance) { } }

If you don't supply a fully-qualified name, it looks like:

use Foo\Bar\SomeClass; class GeneratedClass { public function generatedMethod(\SomeClass $instance) { } }