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| 1 | +package algorithm.leetcode; |
| 2 | + |
| 3 | +import java.util.LinkedList; |
| 4 | +import java.util.Queue; |
| 5 | + |
| 6 | +/** |
| 7 | + * @author: mayuan |
| 8 | + * @desc: 课程表 II |
| 9 | + * @date: 2019/03/13 |
| 10 | + */ |
| 11 | +public class Solution210 { |
| 12 | + public int[] findOrder(int numCourses, int[][] prerequisites) { |
| 13 | + if (numCourses == 0) { |
| 14 | + return null; |
| 15 | + } |
| 16 | + // Convert graph presentation from edges to indegree of adjacent list. |
| 17 | + int[] indegree = new int[numCourses]; |
| 18 | + int[] order = new int[numCourses]; |
| 19 | + int index = 0; |
| 20 | + // Indegree - how many prerequisites are needed. |
| 21 | + for (int i = 0; i < prerequisites.length; i++) { |
| 22 | + indegree[prerequisites[i][0]]++; |
| 23 | + } |
| 24 | + |
| 25 | + Queue<Integer> queue = new LinkedList<Integer>(); |
| 26 | + for (int i = 0; i < numCourses; i++) { |
| 27 | + if (indegree[i] == 0) { |
| 28 | + // Add the course to the order because it has no prerequisites. |
| 29 | + order[index++] = i; |
| 30 | + queue.offer(i); |
| 31 | + } |
| 32 | + } |
| 33 | + // How many courses don't need prerequisites. |
| 34 | + while (!queue.isEmpty()) { |
| 35 | + // Already finished this prerequisite course. |
| 36 | + int prerequisite = queue.poll(); |
| 37 | + for (int i = 0; i < prerequisites.length; i++) { |
| 38 | + if (prerequisites[i][1] == prerequisite) { |
| 39 | + indegree[prerequisites[i][0]]--; |
| 40 | + if (indegree[prerequisites[i][0]] == 0) { |
| 41 | + // If indegree is zero, then add the course to the order. |
| 42 | + order[index++] = prerequisites[i][0]; |
| 43 | + queue.offer(prerequisites[i][0]); |
| 44 | + } |
| 45 | + } |
| 46 | + } |
| 47 | + } |
| 48 | + |
| 49 | + return (index == numCourses) ? order : new int[0]; |
| 50 | + } |
| 51 | +} |
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