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Hash#update is an alias for Hash#merge!
Currently we have merge_bang_vs_[]=
which suggests that Hash#[]= is faster and Hash#merge!() is slower.
But we dont have any suggestions for update_vs_[]=
i.e., Hash#update() vs Hash#[]=.
require 'benchmark/ips' ENUM = (1..100) def fast ENUM.each_with_object({}) do |e, h| h[e] = e end end def slow ENUM.each_with_object({}) do |e, h| h.update(e => e) end end Benchmark.ips do |x| x.report('Hash#[]=') { fast } x.report('Hash#update') { slow } x.compare! end
##### `Hash#update` vs `Hash#[]=` [code](code/hash/update-vs-\[\]=.rb) $ ruby -v code/hash/update-vs-\[\]=.rb ruby 2.6.6p146 (2020-03-31 revision 67876) [x86_64-darwin18] Warming up -------------------------------------- Hash#[]= 7.453k i/100ms Hash#update 4.311k i/100ms Calculating ------------------------------------- Hash#[]= 74.764k (± 1.9%) i/s - 380.103k in 5.085962s Hash#update 43.220k (± 0.8%) i/s - 219.861k in 5.087364s Comparison: Hash#[]=: 74764.0 i/s Hash#update: 43220.1 i/s - 1.73x (± 0.00) slower
Can we extend this to Hash#update()?