fixing a few mroe smallscale typos

chapters/monte_carlo/code/julia/monte_carlo.jl

@@ -21,7 +21,7 @@ function monte_carlo(n::Int64, radius::Float64)
  end
 
  pi_estimate = 4*pi_count/(n*radius^2)
- println("Percent error is: ", signif(100*(pi - pi_estimate), 3), " %")
+ println("Percent error is: ", signif(100*(pi - pi_estimate)/pi, 3), " %")
 end
 
 monte_carlo(10000000, 0.5)

chapters/monte_carlo/monte_carlo.md

@@ -63,7 +63,7 @@ Monte carlo methods are famous for their simplicity.
 It doesn't take too many lines to get something simple going.
 Here, we are just integrating a circle, like we described above; however, there is a small twist and trick.
 Instead of calculating the area of the circle, we are instead trying to find the value of $$\pi$$, and
-rather than integrating the entire circle, we are only integrating the upper left quadrant of the circle from $$0 < x,y < 1$$.
+rather than integrating the entire circle, we are only integrating the upper right quadrant of the circle from $$0 < x,y < 1$$.
 This saves a bit of computation time, but also requires us to multiply our output by $$4$$.
 
 That's all there is to it!