Asynchronous Input Output - Stdout

The purpose of this package is to provide asynchronous variants of the builtin input and print functions. print is known to be relatively slow compared to other operations. input is even slower because it has to wait for user input. While these slow IO operations are being ran, code using asyncio should be able to continuously run.

For Unix/macOS:

python3 -m pip install aio-stdout 

For Windows:

py -m pip install aio-stdout 

With aio_stdout, the aio_stdout.ainput and aio_stdout.aprint functions provide easy to use functionality with organized behaviour.

import asyncio from aio_stdout import ainput, aprint async def countdown(n: int) -> None: """Count down from `n`, taking `n` seconds to run.""" for i in range(n, 0, -1): await aprint(i) await asyncio.sleep(1) async def get_name() -> str: """Ask the user for their name.""" name = await ainput("What is your name? ") await aprint(f"Your name is {name}.") return name async def main() -> None: await asyncio.gather(countdown(15), get_name()) if __name__ == "__main__": asyncio.run(main())

Example output:

15 What is your name? Jane 14 13 12 11 10 9 8 Your name is Jane. 7 6 5 4 3 2 1 

Notice that while the prompt "What is your name? " is being waited for, the countdown continues to aprint in the background, without becoming blocked. The countdown does not, however, display its results until the ainput is completed. Instead it waits for the ainput to finish before flushing out all of the queued messages.

It is worth noting that with naive threading, a normal attempt to use print while waiting on an input leads to overlapping messages. Fixing this behavior requires a lot more work than should be needed to use a simple print or input function, which is why this package exists. To remedy this problem, queues are used to store messages until they are ready to be printed.

Although the asynchronization behaviors of ainput and aprint are nice, sometimes we want to be able to synchronize our messages even more. IO locks provide a way to group messages together, locking the global aio_stdout queues until it finishes or yields access.

import asyncio from aio_stdout import IOLock, ainput, aprint async def countdown(n: int) -> None: """Count down from `n`, taking `n` seconds to run.""" async with IOLock(n=5) as lock: for i in range(n, 0, -1): await lock.aprint(i) await asyncio.sleep(1) async def get_name() -> str: """Ask the user for their name.""" async with IOLock() as lock: name = await lock.ainput("What is your name? ") await lock.aprint(f"Your name is {name}.") return name async def main() -> None: await asyncio.gather(countdown(15), get_name()) if __name__ == "__main__": asyncio.run(main())

Let's try the example again now using the new locks:

15 14 13 12 11 What is your name? Jane Your name is Jane. 10 9 8 7 6 5 4 3 2 1 

Notice that this time the countdown does not immediately yield to the get_name. Instead, it runs 5 messages before yielding control over to get_name. Now, after the lock.ainput finishes, it does not yield to countdown. Instead, it runs its own lock.aprint first. In the meantime, countdown continues to run in the background and flushes all of its buffered messages afterwards.

Since messages may be delayed, it is possible for your asynchronous code to finish running before all messages are displayed, producing confusing results. As such, the best recommended practice is to flush from main before terminating.

from aio_stdout import flush @flush async def main() -> None: ...

Combining all best practices, the final example should look something like this:

import asyncio from aio_stdout import IOLock, ainput, aprint, flush async def countdown(n: int) -> None: """Count down from `n`, taking `n` seconds to run.""" for i in range(n, 0, -1): await aprint(i) await asyncio.sleep(1) async def get_name() -> str: """Ask the user for their name.""" async with IOLock() as lock: name = await lock.ainput("What is your name? ") await lock.aprint(f"Your name is {name}.") return name @flush async def main() -> None: await asyncio.gather(countdown(15), get_name()) if __name__ == "__main__": asyncio.run(main())

• Using input or print instead of ainput and aprint will push a message immediately to the console, potentially conflicting with ainput or aprint.
• Using ainput or aprint instead of lock.ainput and lock.aprint may produce deadlock due to having to wait for the lock to release. As such, the lock is equipped with a default timeout limit of 10 seconds to avoid deadlock and explain to users this potential problem.