Haxe has a special range operator for(i in 0...5) to iterate forward. This does not allow to modify i in place, thus you cannot make it iterate in steps.
You could use a while loop for this:
var total = 10; var step = 2; var i = 0; while(i < total) { trace(i); i += step; } // 0 // 2 // 4 // 6 // 8
This is not always optimal since you need variables outside the loop.
You can also create custom iterators which provide such functionality.
class StepIterator { var end:Int; var step:Int; var index:Int; public inline function new(start:Int, end:Int, step:Int) { this.index = start; this.end = end; this.step = step; } public inline function hasNext() return index < end; public inline function next() return (index += step) - step; }
Usage
Loop in steps of two from 0 to 10.
Learn more about iterators here: https://haxe.org/manual/lf-iterators.html
