Windows batch find folder if statement

Question

Assume a file system with the following format

Folder A
--->Folder 1
--->Folder 2
--->Folder 3 etc..
Folder B
--->Folder 4
--->Folder 2
--->Folder 3
Folder C
--->Folder 1
--->Folder 2
--->Folder 3
--->Folder 4

I need to go one level deep, and only one level deep, and search for 'Folder 1'. If Folder 1 is there, then remove Folder 2 and Folder 3.

I can use a Windows batch file or some other programing language.

What have you tried and what is not working with it? Can you post any of your example scripts? — jscott
– jscott, Commented Feb 26, 2013 at 14:26
for /D /R c:\test %X IN (*.something) DO echo %X > test.txt. How do I match an exact folder name though? — user1983916
– user1983916, Commented Feb 26, 2013 at 14:45
Can you use Powershell? And will you know the sub-folder names (e.g. Folder 2, Folder 3...) ahead of time? Or do you want to just delete everything under the first level folders if "folder 1" exists? — jscott
– jscott, Commented Feb 26, 2013 at 14:52

Khaled · Accepted Answer · 2013-02-26 15:10:32Z

The following script (or line) will check all directories within the current directory one level deep for the presence of Folder1\NUL, a well-known ugly trick to distinguish files from directories. Be careful around directories that contain spaces; they may be parsed as two separate locations for rmdir to do its damage.

for /D %%i in (*) do ( if exist .\%%i\Folder1\NUL ( rmdir /S .\%%i\Folder2 rmdir /S .\%%i\Folder3 ) )

looks like does every folder in the current directory but not into the folders in that directory? For example in my post above, I need to go into Folder A, B and C and find the folder — user1983916
– user1983916, Commented Feb 26, 2013 at 15:01

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