Trying to start script but keep getting error syntax error near unexpected token `stop'

Question

#!/bin/bash # case “$1” in start) echo -n “Starting Queue Manager” /opt/mqm/bin/strmqm QMPROD1 sleep 10 echo -n “Started Queue Manager” # echo “IBM ACE” /opt/ace-12.0.4.0/server/bin/mqsistart.bin IIBPROD1 sleep 10 echo “Pokrenut ACE” ;; stop) echo -n “Stopping IBM ACE” /opt/ace-12.0.4.0/server/bin/mqsistop.bin IIBPROD1 echo -n “Stop IBM ACE” kill -9 'ps -ef | grep ace' echo -n “Ok” # echo -n “Stopping Queue: Queue Manager” /opt/mqm/bin/endmqm QMPROD1 echo -n “Stop” kill -9 'ps -ef | grep mqm' sleep 10 ;; $0 stop $0 start *) echo “Usage: $0 start | stop” esac exit 0 

[root@ct init.d]# sh ace.sh start ace.sh: line 34: syntax error near unexpected token stop' ace.sh: line 34: $0 stop' My OS is Centos 8

Answer 1

I created new script which is similar to one above.

#!/bin/bash start() { echo "Starting Queue Manager" /opt/mqm/bin/strmqm QMPROD1 sleep 2 echo -n "Started Queue Manager" echo -n "Starting IBM ACE" /opt/ace-12.0.4.0/server/bin/mqsistart IIBPROD1 sleep 2 echo -n "Started IBM ACE(Svaka Cast)" } stop() { echo -n "Stopping IBM ACE" /opt/ace-12.0.4.0/server/bin/mqsistop IIBPROD1 sleep 2 echo -n "Stopped IBM ACE" echo "stopping Queue Manager" /opt/mqm/bin/endmqm QMPROD1 sleep 2 echo "Ugasen Queue Manager" } case "$1" in start) start ;; stop) stop;; *) echo "usage $0 start|stop" >&2 exit 1 ;; esac