cmd - run a batch file after all other concurrent batch files finish

Question

I have a simple batch file which calls other batch files, it looks like this:

start /b run_part1.bat start /b run_part2.bat start /b run_part3.bat start /b run_part4.bat run_last.bat // fires immediately, how to make this line wait until above finishes? 

With the /b the first 4 files will run concurrently. All will finish within 1.5 hours.

I need another script to do some cleaning up after all the four files finish. However the run_last.bat will not wait for the first 4 files, it is called at the same time with the first 4.

Is there a way to achieve it?

Thank you.

Answer 1

Stop using the antiquated command prompt and use Powershell. You can use the ThreadJob module, as described in this excellent answer on SO:

$commands = { ./run_part1.bat }, { ./run_part2.bat }, { ./run_part3.bat }, { ./run_part4.bat } $jobs = $commands | Foreach-Object { Start-ThreadJob $_ } $jobs | Receive-Job -Wait -AutoRemoveJob ./run_last.bat 

Answer 2

you can use CALL ,it calls one bath file from another bath file

for more information check https://www.robvanderwoude.com/call.php

Answer 3

There is nothing built-in to batch files to handle this.

You can modify the 4 batch files to create a flag file when they are done. Then in the main batch file, run a loop looking for the flag files with a call to timeout /t 10 in the loop to slow down the checks.