1
$\begingroup$

consider a finite set $\mathcal{P}(x,y)=\lbrace(x_1,y_1),\dots,\,(x_n,y_n)\rbrace$ of points in the Euclidean plane and let $\mathrm{DT}(x,y)$ be the Delaunay triangulation of $\mathcal{P}(x,y)$

Define the cost $|\mathrm{DT}(x,y)|$ of the Delaunay triangulation to be $\sum\limits_{e_{ij}\in \mathrm{DT}}|y_i-y_j|$, i.e. the sum over the absolute difference between the y-coordinates of two points that are adjacent to the same edge in the triangulation.

If we scale the x-coordinates by $\alpha$ then the edge sets of $\mathrm{DT}(x,y)$ may be different from the edge set of $\mathrm{DT}(\alpha x,y)$ and thus their costs may also be different, leading to the

Question:

how can $\alpha_0: |\mathrm{DT}(\alpha_0 x,\,y)|= \min_\alpha|\mathrm{DT}(\alpha x,\,y)|\lt|\mathrm{DT}((\alpha_0+\varepsilon)\cdot x,\,y)|\ \forall \varepsilon,\alpha\gt 0$ be calculated efficiently?

The question may also be extended to asking for the maximal range $[\alpha_0,\alpha_1]$ outside of which the cost doesn't change but replacing either $\alpha_0$ with $\alpha_0+\varepsilon$ or $\alpha_1$ with $\alpha_1-\varepsilon$ incurs a change of cost.

Edit
I restate the problem to:

determine the parameters of an affine transformation of a finite point set in the Euclidean plane that renders the minimal angle in the Delaunay triangulation of the transformed point set maximal.

$\endgroup$

0

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.