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1 change: 1 addition & 0 deletions L-I/0006 Repeat a String (L-I)/.gitignore
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node_modules
45 changes: 45 additions & 0 deletions L-I/0006 Repeat a String (L-I)/README.md
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# 0006 Repate a String Num times ( L-I )
## Problem

repeat a given string `str` for `num` of times, and return empty in case the num is zero or negative number, and without using `.repeat()` method.

## Test Cases

- str = "A" and num = 5, the function should return "AAAAA".
- str = "A" and num = 0, the function should return "".
- str = "A" and num = 2, the function should return "AA".
- str = "A" and num = -1, the function should return "".
## Solution

```javascript
const repeatStringNumTimes = (str, num) => {
if (num < 1) {
return "";
}
// here I used recursion technique to solve the problem
return str + repeatStringNumTimes(str, num - 1);
};

console.log(repeatStringNumTimes("abc", 3));
```

## How it works

- The function takes two parameters.
- The first is a string, and the second a integer number.
- If the the second parameter is number and positive, it will return the string * number of times.

## References

- [Khan Academy](https://www.khanacademy.org/computing/computer-science/algorithms/recursive-algorithms/a/recursion)
- [FreeCodeCamp](https://www.freecodecamp.org/news/three-ways-to-repeat-a-string-in-javascript-2a9053b93a2d/)

## Problem Added By
- [GitHub](https://github.com/ibr5500)
- [LinkedIn](https://www.linkedin.com/in/ibrahim-ahmat/)
- [Twitter](https://twitter.com/ibr_ahmat)

## Contributing
Pull requests are welcome. For major changes, please open an issue first to discuss what you would like to change.

Please make sure to update tests as appropriate.
11 changes: 11 additions & 0 deletions L-I/0006 Repeat a String (L-I)/challenge.js
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const repeatStringNumTimes = (str, num) => {
if (num < 1) {
return "";
}
// here I used recursion technique to solve the problem
return str + repeatStringNumTimes(str, num - 1);
};

// console.log(repeatStringNumTimes("AaA ", 3));

module.exports = repeatStringNumTimes;
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