Replace ParamList with Group #2142
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Summary of changes
No functional changes. I've wanted to better understand the parsing of SPARQL, and have found that
ParamList
makes the parsing unnecessarily more complex. ReplacingParamList
with the built-inGroup
operator simplifies the ability to understand how a SPARQL query is being parsed.In order to replace
ParamList
withGroup
, I just did a find and replace ofParamList(foo)
withGroup(Param(foo))
. Perhaps replacing instances ofZeroOrMore(ParamList(foo))
should be replaced withGroup(ZeroOrMore(Param(foo))
instead ofZeroOrMore(Group(Param(foo))
, but I'm not too sure of the benefits of one over the other, so I instead opted for what semantically matches what we had prior to this change.Checklist