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Dharan Ganesan
Dharan Ganesan

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Day 19: Retry

#day19 #100daysofcode #javascript

Question

Write a function retryAsyncOperation that takes an asynchronous operation represented as a Promise and retries it a certain number of times before rejecting the Promise.

function retryAsyncOperation(asyncFunction, retries, delay) { // Your code here } // Example usage function simulateAsyncOperation() { return new Promise((resolve, reject) => { const success = Math.random() < 0.5; // Simulating success half of the time setTimeout(() => { if (success) { resolve("Success"); } else { reject("Error"); } }, 1000); }); } retryAsyncOperation(simulateAsyncOperation, 3, 1000) .then(result => console.log("Result:", result)) .catch(error => console.error("All attempts failed:", error));
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dhrn profile image
Dharan Ganesan • 
function retryAsyncOperation(asyncFunction, retries, delay) { return new Promise((resolve, reject) => { function attemptOperation(attemptsLeft) { asyncFunction() .then(resolve) .catch(error => { if (attemptsLeft > 0) { setTimeout(() => attemptOperation(attemptsLeft - 1), delay); } else { reject(error); } }); } attemptOperation(retries); }); }
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