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Deepak Raj
Deepak Raj

Posted on • Edited on • Originally published at codeperfectplus.com

Day 2 - 10DaysOfJavaScript

#challenge #javascript #beginners #programming

Day 2 - 10DaysOfJavaScript

Day 2: Conditional Statements: If-Else

  • An integer value score is provided for a students test
  • 0 ≤ score ≤ 30
  • It must return the letter corresponding to grade 
function getGrade(score) { let grade; // Write your code here if(score<=5) { grade="F"; }else if(score<=10) { grade='E'; }else if(score<=15) { grade='D' }else if(score<=20) { grade ='C' }else if(score<=25) { grade ='B' }else if(score<=30) { grade='A' } return grade; }
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Day 2: Conditional Statements: Switch

  • A string is provided where its length is 1 ≤ s ≤ 100
  • Given the following legend, return the correct value based on the first letter 
function getLetter(s) { let letter; // Write your code here switch (true) { case 'aeiou'.includes(s[0]): letter = 'A'; break; case 'bcdfg'.includes(s[0]): letter = 'B'; break; case 'hjklm'.includes(s[0]): letter = 'C'; break; case 'npqrstvwxyz'.includes(s[0]): letter = 'D'; break; } return letter; }
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Day 2: Loops

  • Given a string of s of any length
  • Output, in order, the vowels of that string on each new line
  • Right after, output, in order, the consonants of that string on each new line 
/* * Complete the vowelsAndConsonants function. * Print your output using 'console.log()'. */ function vowelsAndConsonants(s) { let vowels = ['a','e','i','o','u']; for(let v of s) { if(vowels.includes(v)) console.log(v); } for(let v of s) { if(!vowels.includes(v)) console.log(v); } } string = 'javascriptloops' vowelsAndConsonants(string)
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Top comments (1)

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pentacular profile image
pentacular •

It would be simpler without the grade variable.
You can just return the value directly.

I also suggest using more spaces and not writing if(x) which looks like a function call.

function getGrade (score) { if (score <= 5) { return "F"; } else if (score <= 10) { ... } }

Likewise here, although here we can also use better variable names.

function getLetter (string) { const letter = string[0]; // Write your code here switch (true) { case 'aeiou'.includes(letter): return 'A'; case 'bcdfg'.includes(letter): ... } }

You already know that includes works on strings, so why stop now?
And let's use const if you're not going to reassign something.

function vowelsAndConsonants (string) { const vowels = 'aeiou'; ... }