✅ Problem 1: Two Sum
📝 Problem Statement:
- Given an integer input, the objective is check whether the given integer is Positive or Negative. In order to do so we have the following methods,
Example
Input: num = 12; Output: The number is positive Approach
1. Create a function. 2. Take a number as input. 3. Check if the number is less than 0 — if so, the number is negative. 4. Otherwise, the number is positive. 
Js Code
function checkPositiveOrNegative(num) { if (num < 0) { return 'The number is negative'; } else { return 'The number is positive'; } } console.log(checkPositiveOrNegative(12)); // Output: The number is positive console.log(checkPositiveOrNegative(0)); // Output: The number is positive console.log(checkPositiveOrNegative(-10)); // Output: The number is negative ✅ Problem 2: Even or Odd
📝 Problem Statement:
- Check whether the given number is Even or Odd
Example
Input: num = 12; Output: The number is Even Input: num = 11; Output: The number is Odd Approach
1. Create a function called CheckEvenOdd. 2. Take a number as input. 3. If the number is divisible by 2 , then the number is even. 4. Otherwise, the number is odd. 
Js Code
function CheckEvenOdd(num) { if (num % 2 === 0) { return 'The Number is Even'; } else { return 'The Number is Odd'; } } console.log(CheckEvenOdd(2)); // Output: The Number is Even console.log(CheckEvenOdd(3)); // Output: The Number is Odd console.log(CheckEvenOdd(5)); // Output: The Number is Odd console.log(CheckEvenOdd(8)); // Output: The Number is Even //
✅ Problem 3: Sum of First N Natural Numbers
📝 Problem Statement:
- Find the Sum of First N Natural Numbers.
- Natural numbers start from 1 and go on infinite.
Example
Input: num = 5; Output: 15 Input: num = 10; Output: 55 Approach
1. Create a function called SumOfNaturalNumber. 2. Initialize a variable `sum` to 0. 3. Run a loop from 1 to the given number `num`. 4. In each iteration, add the current number to `sum`. 5. After the loop ends, return the 
Js Code
// Sum of First N Natural Numbers function SumOfNaturalNumber(num) { let sum = 0; for (let i = 1; i <= num; i++) { sum += i; } return sum; } // Test cases console.log(SumOfNaturalNumber(5)); // Output: 15 console.log(SumOfNaturalNumber(10)); // Output: 55 console.log(SumOfNaturalNumber(2)); // Output: 3 
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