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Daily Challenge #148 - Disemvowel Trolls

dev.to staff on December 29, 2019

Setup Trolls are invading the comment section! To deal with the threat, write a function that takes a string and returns a new string with all vow...

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Andreas Jakof • Dec 29 '19 • Edited

In C#

public static readonly List<Char> LowerCaseVowels = new List<Char> {'a', 'e', 'i', 'o', 'u'}; public static bool IsLowerCaseVowel(this char c) => LowerCaseVowels.Contains(c); public static string RemoveVowels(string input) => new string(input.Where(c => !c.ToLowerInvariant().IsLowerCaseVowel()));

Praneet Nadkar • Dec 30 '19

Or may be just

var cleaned = Regex.Replace(input,"[aeiou]", "", RegexOptions.IgnoreCase);

Andreas Jakof • Dec 30 '19

Nice One!

Jaime Sánchez M. • Dec 29 '19 • Edited

In Ts:

const removeVowels = (text: string) => text.replace(/[aeiou]/gi, '');

Ashwin Shenoy • Dec 29 '19

Python solution.

def disemvowel(string): """Removes all occurences of vowel from the string. Args: string (str): The input string. Returns: temp_string (str): The resultant string with vowels removed. """ final_string = "" for i in string: if i.lower() in ["a", "e", "i", "o", "u"]: continue else: final_string += i return final_string if __name__ == '__main__': print(disemvowel("This website is for losers LOL!"), "Ths wbst s fr lsrs LL!")

Rafael Acioly • Dec 30 '19

you could use regex to keep it simple :)

Ashwin Shenoy • Dec 30 '19

I am yet to study about regexes :)

Ryan Burmeister-Morrison • Dec 30 '19 • Edited

Here's a Ruby submission!

# Remove all vowels ('y' not included) from a string. # # @param [String] the string to strip vowels from # # @return [String] the resulting string def disemvowel(str) str.split('').select { |ch| !ch.match(/^[aeiou]$/i) }.join('') end puts disemvowel("This website is for losers LOL!") puts disemvowel("No newbies allowed, go to #beginners") puts disemvowel("LULZ TROLLED")

Here's a link to the Repl.it: repl.it/@rburmorrison/DevToChallen...

Amin • Dec 29 '19

Elm

module Main exposing (main) import Char exposing (toLower) import List exposing (member) import String exposing (filter) isForbiddenInsensitive : List Char -> Char -> Bool isForbiddenInsensitive characterList character = member (toLower character) characterList removeVowels : String -> String removeVowels = filter <| not << isForbiddenInsensitive [ 'a', 'e', 'i', 'o', 'u' ]

Example.

Brett Martin • Dec 30 '19

Standard ML of New Jersey Solution

 val vowels = [#"a", #"e", #"i", #"o", #"u"] fun member_of (item, list) = List.exists (fn x => x = item) list fun disemvowel s = implode (List.filter (fn x => not(member_of(Char.toLower x, vowels))) (explode s))

Yechiel Kalmenson • Dec 29 '19 • Edited

Ruby:

def disemvowel(string) string.gsub(/[aeiou]/i, "") end

Kasem777 • Jun 10 '20 • Edited

Liquid syntax error: Unknown tag 'def'

Kevin Mas Ruiz • Dec 29 '19

Some unfancy Common Lisp:

(defun remove-vowels (text) (flet ((vowel-p (char) (find char "aeiouAEIOU" :test #'char=))) (remove-if #'vowel-p text)))

Rafael Acioly • Dec 30 '19

Python solution 🐍

import re VOWELS_REGEX = r"[aeiou]" def removeVowels(message: str) -> str: return re.sub(VOWELS_REGEX, '', message, flags=re.IGNORECASE)

fitsum • Dec 30 '19 • Edited

const disemvowel = (str) => str.replace(/[aeoiu]/gi, '');