Rings and Rods | Leetcode Problem Solution Using Bit Manipulation

Problem Statement

There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.

You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:

• The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').
• The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').

For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.

Return the number of rods that have all three colors of rings on them.

Sample Input
B0B6G0R6R0R6G9

Sample Output
1

Explanation

• The rod labeled 0 holds 3 rings with all colors: red, green, and blue.
• The rod labeled 6 holds 3 rings, but it only has red and blue.
• The rod labeled 9 holds only a green ring. Thus, the number of rods with all three colors is 1.

Link to question: https://leetcode.com/problems/rings-and-rods/

Solution (C++)

class Solution { public int countPoints(String rings) { int count, n=rings.length(); int rods[]=new int[10]; Arrays.fill(rods, 0); for(int i=0; i<n; i+=2) { char color=rings.charAt(i); int rod=rings.charAt(i+1)-48; switch(color) { case 'R': rods[rod]=rods[rod] | 1; break; case 'G': rods[rod]=rods[rod] | 2; break; case 'B': rods[rod]=rods[rod] | 4; break; } } count=0; for(int item: rods) count+=item==7?1:0; return count; } };