Given a string paragraph and a string array of the banned words banned, return the most frequent word that is not banned. It is guaranteed there is at least one word that is not banned, and that the answer is unique.
The words in paragraph are case-insensitive and the answer should be returned in lowercase.
import re class Solution: def mostCommonWord(self, paragraph: str, banned: List[str]) -> str: #List words in paragraph, replacing punctuation with ' ' and all lower case paragraph = re.subn("[.,!?;']", ' ', paragraph.lower())[0].split(' ') #Remove any '' or words in banned from paragraph list paragraph = list(filter(lambda x: x not in banned + [''], paragraph)) #Return most common word in filtered list return Counter(paragraph).most_common(1)[0][0] 
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