Credit Card Mask π³
- Usually when you buy something, you're asked whether your credit card number,
- phone number or answer to your most secret question is still correct.
- However, since someone could look over your shoulder,
you don't want that shown on your screen. Instead, we mask it.
Your task is to write a function maskify,
which changes all but the last four characters into '#'.
Examples:
"4556364607935616" --> "############5616" "64607935616" --> "#######5616" "1" --> "1" "" --> "" "What was the name of your first pet?" "Skippy" --> "##ippy" "Nananananananananananananananana Batman!" --> "####################################man!" Task URL: https://www.codewars.com/kata/5412509bd436bd33920011bc/python
My Solution:
def maskify(cc): """ Masks the credit card number by replacing all but the last four characters with '#' Args: cc (str): The credit card number as a string Returns: str: The masked credit card number """ credit_card = str(cc) if len(credit_card) == 1 or len(credit_card) == 4: return credit_card if credit_card == "": return "" start = credit_card[0:-4] end = credit_card[-4:] hash = len(start) * '#' hash_credit_card = "".join([hash, end]) return hash_credit_card Code Snapshot:
Learn Python
Python top free courses from Courseraππ―π
π₯

Top comments (0)