*Memos:
- My post explains a tuple.
- My post explains the tuple with slicing and copy.
- My post explains variable assignment.
- My post explains shallow copy and deep copy.
You can access a tuple by indexing as shown below. *Indexing can be done with one or more [index]:
v = () # 1D tuple print(v) # () v = ('a',) # 1D tuple v = 'a', # 1D tuple v = (('a',)) # 1D tuple print(v[0]) print(v[-1]) # a v = ('a', 'b', 'c', 'd', 'e', 'f', 'g', 'h') # 1D tuple v = 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h' # 1D tuple print(v[0], v[1], v[2], v[3], v[4], v[5], v[6], v[7]) print(v[-8], v[-7], v[-6], v[-5], v[-4], v[-3], v[-2], v[-1]) # a b c d e f g h v = (('a', 'b', 'c', 'd'), ('e', 'f', 'g', 'h')) # 2D list print(v[0], v[1]) print(v[-2], v[-1]) # ('a', 'b', 'c', 'd') ('e', 'f', 'g', 'h') print(v[0][0], v[0][1], v[0][2], v[0][3], v[1][0], v[1][1], v[1][2], v[1][3]) print(v[-2][-4], v[-2][-3], v[-2][-2], v[-2][-1], v[-1][-4], v[-1][-3], v[-1][-2], v[-1][-1]) # a b c d e f g h v = ((('a', 'b'), ('c', 'd')), (('e', 'f'), ('g', 'h'))) # 3D list print(v[0], v[1]) print(v[-2], v[-1]) # (('a', 'b'), ('c', 'd')) (('e', 'f'), ('g', 'h')) print(v[0][0], v[0][1], v[1][0], v[1][1]) print(v[-2][-2], v[-2][-1], v[-1][-2], v[-1][-1]) # ('a', 'b') ('c', 'd') ('e', 'f') ('g', 'h') print(v[0][0][0], v[0][0][1], v[0][1][0], v[0][1][1], v[1][0][0], v[1][0][1], v[1][1][0], v[1][1][1]) print(v[-2][-2][-2], v[-2][-2][-1], v[-2][-1][-2], v[-2][-1][-1], v[-1][-2][-2], v[-1][-2][-1], v[-1][-1][-2], v[-1][-1][-1]) # a b c d e f g h You can use index() to get the index of an element from a tuple as shown below:
*Memos:
- The 1st argument is
x(Required) for an index. - The 2nd argument is
start(Optional) for the start of an index. - The 3rd argument is
end(Optional) for the end of an index. - If the element doesn't exist, there is error.
- Don't use
x=,start=andend=.
v = ('a', 'b', 'c', 'd', 'a', 'b', 'c', 'd') print(v.index('b')) # 1 print(v.index('b', 2)) # 5 print(v.index('b', 2, 6)) # 5 print(v.index('b', 2, 5)) # ValueError: tuple.index(x): x not in tuple You can use count() to count how many selected elements there are in a tuple as shown below:
*Memos:
- The 1st argument is
x(Required) for an element. - *Don't use
x=.
v = ('a', 'b', 'c', 'a', 'b', 'b', 'a', 'b') print(v.count('a')) # 3 print(v.count('b')) # 4 print(v.count('c')) # 1 print(v.count('d')) print(v.count('A')) # 0 You can use sorted() to sort a tuple as shown below. Finally, a list is returned:
*Memos:
- The 1st argument is
iterable(Required) for an iterable. *Don't useiterable=. - The 2nd argument is
key(Optional-Default:None) for a function. - The 3rd argument is
reverse(Optional-Default:False) to reverse a list. -
sorted()creates a copy. *Be careful,sorted()does shallow copy instead of deep copy as my issue.
v = (-4, 1, 5, 3, -2) print(sorted(v)) # [-4, -2, 1, 3, 5] print(sorted(v, reverse=True)) # [5, 3, 1, -2, -4] print(sorted(v, key=abs)) # [1, -2, 3, -4, 5] print(sorted(v, key=abs, reverse=True)) # [5, -4, 3, -2, 1] v = ("apple", "Banana", "Kiwi", "cherry") # Case sensitive sort print(sorted(v)) # ['Banana', 'Kiwi', 'apple', 'cherry'] # Case insensitive sort print(sorted(v, key=str.upper)) print(sorted(v, key=str.lower)) # ['apple', 'Banana', 'cherry', 'Kiwi'] # Sort by the length of a word print(sorted(v, key=len)) # ['Kiwi', 'apple', 'Banana', 'cherry'] 
Top comments (0)