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python获取安卓包名与activity方法

发布时间:2020-09-10 09:48:43 来源:网络 阅读:633 作者:知止内明 栏目:编程语言

代码如下:

 def adbcmdapk(filepath): if not os.path.exists(filepath): return 0 getPackageActivity = 'aapt d badging %s |findstr "package launchable-activity"' % (filepath) result = os.popen(getPackageActivity).readlines() packageandpackage = {} package = "" activity = "" for i in range(len(result)): if "package" in result[i]: nameNumber = result[i].find("e='") versionCodeNumber = result[i].find("' v") package = result[i][nameNumber + 3:versionCodeNumber] if "launchable-activity" in result[i]: nameNumber = result[i].find("e='") versionCodeNumber = result[i].find("' l") activity = result[i][nameNumber + 3:versionCodeNumber] # 添加到字典中 packageandpackage[package] = activity return packageandpackage

测试类

 if __name__ == '__main__': pa = "E:\\toontest3.8.1.apk" print(adbcmdapk(pa))

结果:

{'com.systoon.toon': 'com.systoon.toon.user.login.view.WelcomeActivity'}

第二种方式:

class ApkInfo(): def __init__(self, apkPath): self.apkPath = apkPath def getApkBaseInfo(self): p = subprocess.Popen("aapt dump badging %s" % self.apkPath, stdout=subprocess.PIPE, stderr=subprocess.PIPE, stdin=subprocess.PIPE, shell=True) (output, err) = p.communicate() match = re.compile("package: name='(\S+)' versionCode='(\d+)' versionName='(\S+)'").match(output.decode()) if not match: raise Exception("can't get packageinfo") packagename = match.group(1) versionCode = match.group(2) versionName = match.group(3) print('packagename:' + packagename) print('versionCode:' + versionCode) print('versionName:' + versionName) return packagename, versionName, versionCode

if name == 'main':
ApkInfo(r"E:\toontest3.8.1.apk").getApkBaseInfo()

结果:

packagename:com.systoon.toon
versionCode:1803060450
versionName:3.8.1

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