当一个函数有多个返回值时,可以使用以下几种方法来解决这个问题:
void func(int a, int b, int* sum, int* difference) { *sum = a + b; *difference = a - b; } int main() { int a = 10, b = 5, sum, difference; func(a, b, &sum, &difference); printf("Sum: %d\n", sum); printf("Difference: %d\n", difference); return 0; }
typedef struct { int sum; int difference; } Result; Result func(int a, int b) { Result result; result.sum = a + b; result.difference = a - b; return result; } int main() { int a = 10, b = 5; Result result = func(a, b); printf("Sum: %d\n", result.sum); printf("Difference: %d\n", result.difference); return 0; }
int sum; int difference; void func(int a, int b) { sum = a + b; difference = a - b; } int main() { int a = 10, b = 5; func(a, b); printf("Sum: %d\n", sum); printf("Difference: %d\n", difference); return 0; }
以上是几种常见的解决多个返回值问题的方法,根据具体情况选择合适的方法来解决问题。