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c# beginreceive能设置超时时间吗

c#
小樊
158
2024-12-04 07:21:51
栏目: 编程语言

是的,在C#中,BeginReceive方法可以设置超时时间。为了实现这个功能,您需要使用Socket类的SetSocketOption方法来设置SocketOptionName.ReceiveTimeout选项。以下是一个示例:

using System; using System.Net; using System.Net.Sockets; using System.Text; using System.Threading.Tasks; class Program { static void Main(string[] args) { IPAddress ipAddress = IPAddress.Parse("127.0.0.1"); int port = 12345; using (Socket socket = new Socket(ipAddress.AddressFamily, SocketType.Stream, ProtocolType.Tcp)) { socket.Connect(ipAddress, port); // 设置接收超时时间(单位:毫秒) int receiveTimeout = 5000; socket.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReceiveTimeout, receiveTimeout); byte[] buffer = new byte[1024]; IAsyncResult result = socket.BeginReceive(buffer, 0, buffer.Length, SocketFlags.None, null); // 检查是否在超时时间内接收到数据 if (result.AsyncWaitHandle.WaitOne(receiveTimeout, true)) { int bytesReceived = socket.EndReceive(result); string receivedData = Encoding.UTF8.GetString(buffer, 0, bytesReceived); Console.WriteLine("Received data: " + receivedData); } else { Console.WriteLine("Receive operation timed out."); } } } } 

在这个示例中,我们首先创建一个Socket对象并连接到指定的IP地址和端口。然后,我们使用SetSocketOption方法设置接收超时时间为5000毫秒(5秒)。接下来,我们使用BeginReceive方法开始接收数据,并使用AsyncWaitHandle.WaitOne方法检查是否在超时时间内接收到数据。如果在超时时间内接收到数据,我们使用EndReceive方法结束接收操作并处理接收到的数据。如果未在超时时间内接收到数据,我们将输出一条超时消息。

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