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Remove the element with the specified key from the Hashtable in C#
To remove the element with the specified key from the Hashtable, the code is as follows −
Example
using System; using System.Collections; public class Demo {    public static void Main(){       Hashtable hash = new Hashtable(10);       hash.Add("1", "A");       hash.Add("2", "B");       hash.Add("3", "C");       hash.Add("4", "D");       hash.Add("5","E");       hash.Add("6", "F");       hash.Add("7", "G");       hash.Add("8","H");       hash.Add("9", "I");       hash.Add("10", "J");       Console.WriteLine("Hashtable Key and Value pairs...");       foreach(DictionaryEntry entry in hash){          Console.WriteLine("{0} and {1} ", entry.Key, entry.Value);       }       Console.WriteLine("Is the Hashtable having fixed size? = "+hash.IsFixedSize);       Console.WriteLine("Count of entries in Hashtable = "+ hash.Count);       hash.Remove("5");       Console.WriteLine("Count of entries in Hashtable (updated) = "+hash.Count);    } }  Output
This will produce the following output −
Hashtable Key and Value pairs... 10 and J 1 and A 2 and B 3 and C 4 and D 5 and E 6 and F 7 and G 8 and H 9 and I Is the Hashtable having fixed size? = False Count of entries in Hashtable = 10 Count of entries in Hashtable (updated) = 9
Example
Let us see another example −
using System; using System.Collections; public class Demo {    public static void Main(){       Hashtable hash = new Hashtable(10);       hash.Add("One", "Marketing");       hash.Add("Two", "Operations");       hash.Add("Three", "Finance");       hash.Add("Four", "IT");       hash.Add("Five","Sales");       hash.Add("Six", "Purchase");       Console.WriteLine("Hashtable Key and Value pairs...");       foreach(DictionaryEntry entry in hash){          Console.WriteLine("{0} and {1} ", entry.Key, entry.Value);       }       Console.WriteLine("Count of entries in Hashtable = "+ hash.Count);       hash.Remove("Two");       hash.Remove("Three");       hash.Remove("Four");       Console.WriteLine("Count of entries in Hashtable (updated) = "+hash.Count);    } }  Output
This will produce the following output −
Hashtable Key and Value pairs... One and Marketing Five and Sales Three and Finance Two and Operations Four and IT Six and Purchase Count of entries in Hashtable = 6 Count of entries in Hashtable (updated) = 3
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